х — у + 2z — 2х + у — 2z - 2w 3 —2 w = -1 - - | -x + 2y – 4z + w = 1 3x 3w = -3
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Question
Solve the linear system by Gauss–Jordan elimination
![y + 2z -
w = -1
-
2х + у — 2z - 2w 3D —2
—х + 2у — 4z+ w %3D
- 3w = -3
1
3x](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fd2082cb3-95cf-4561-a9bf-97e35996c7c7%2F2b919c5c-9256-4170-9c40-ca5ac30453f8%2Fvlvo0w_processed.jpeg&w=3840&q=75)
Transcribed Image Text:y + 2z -
w = -1
-
2х + у — 2z - 2w 3D —2
—х + 2у — 4z+ w %3D
- 3w = -3
1
3x
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