Answered: h the 2d spacing of 0.4028 nm

Name: h the 2d spacing of 0.4028 nm
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Determine the element with the lowest atomic number that can be detected by wavelength dispersive x-ray spectroscopy that uses the LiF (200) crystal with the 2d spacing of 0.4028 nm

hkl
20
d(nm)
h²+k?+P
V(h?+k?+P)
a(nm)
111
38.33
0.2349
1.732
0.407
200
45
0.2015
4
2
0.403
220
67.17
0.1394
2.828
0.394
3.
00

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