х - О.1x2 - 0.1у? %3D0.8 y - 0.1x – 0.1xy² =0.8 Newton formula ; df -) x0,y0 dj x0, v0 dy dg. dg. -g(x,, Yo) x0, у0 x0, v0 dx dy

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
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Solve the following set of non-linear equations for the initial values of X0 = 0.5 and Y0 = 0.5 by Newton's method.

x - 0.1x2 – 0.1y2 =0.8
y - 0.1x – 0.1xy? =0.8
Newton formula;
df
df
-1 (Xp, Yo)
x0, v0
x0, v0
dy
dg.
dg
-g(x, Yo)_
x0, v0
x0, у0
dx
dy
Transcribed Image Text:x - 0.1x2 – 0.1y2 =0.8 y - 0.1x – 0.1xy? =0.8 Newton formula; df df -1 (Xp, Yo) x0, v0 x0, v0 dy dg. dg -g(x, Yo)_ x0, v0 x0, у0 dx dy
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