H CI Question 20.b of 24 Describe the structure, bonding, and properties of the organic functional group provided in the questions below. Identify the type of bonding in the circled atom in this structure. A) four sigma bonds B) three sigma bonds, one pi bond and no nonbonding electrons C) two sigma bonds, two pi bonds and no nonbonding electrons D) two pi bonds and four nonbonding electrons E) one sigma bond and six nonbonding electrons Submit +

Chemistry
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Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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**Educational Website Content: Organic Chemistry**

### Topic: Understanding the Structure, Bonding, and Properties of Organic Functional Groups

#### Question 20.b of 24

**Objective:** Describe the structure, bonding, and properties of the organic functional group provided in this question.

**Task:** Identify the type of bonding in the circled atom in the provided structure.

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**Question:** Identify the type of bonding in the circled atom in this structure.

An illustration is provided featuring a chemical structure with a carbon backbone. A chlorine atom (Cl) is circled, indicating focus on the bonds associated with this chlorine atom. The chlorine atom is connected to a carbon atom, which in turn is bonded to other atoms or groups.

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**Answer Choices:**

A. Four sigma bonds

B. Three sigma bonds, one pi bond and no nonbonding electrons

C. Two sigma bonds, two pi bonds and no nonbonding electrons

D. Two pi bonds and four nonbonding electrons

E. One sigma bond and six nonbonding electrons

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Please select the correct answer from the above options and proceed with your solution.

**Note:** Understanding electron configurations and bonding types (sigma and pi bonds, and nonbonding electrons) will aid in identifying the correct bonding type for the chlorine atom in this structure.

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**Detailed Explanation:**

To answer this question, recall the following:

- **Sigma (σ) Bonds:** These are single covalent bonds formed from head-on overlapping of atomic orbitals.
- **Pi (π) Bonds:** These are additional bonds in double and triple bonds, formed from the side-to-side overlapping of p orbitals.
- **Nonbonding Electrons (Lone Pairs):** Electrons that are not involved in bonding but reside on an atom.

Use this foundational knowledge to determine how chlorine bonds in this structure, considering it typically forms one sigma bond with its connected carbon and has three pairs of nonbonding electrons.

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By solving this question, you will enhance your understanding of bonding structures in organic compounds and the behavior of chlorinated hydrocarbons.

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For further reading and detailed examples, refer to our modules on **Covalent Bonding** and **Molecular Geometry**.

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Transcribed Image Text:--- **Educational Website Content: Organic Chemistry** ### Topic: Understanding the Structure, Bonding, and Properties of Organic Functional Groups #### Question 20.b of 24 **Objective:** Describe the structure, bonding, and properties of the organic functional group provided in this question. **Task:** Identify the type of bonding in the circled atom in the provided structure. --- **Question:** Identify the type of bonding in the circled atom in this structure. An illustration is provided featuring a chemical structure with a carbon backbone. A chlorine atom (Cl) is circled, indicating focus on the bonds associated with this chlorine atom. The chlorine atom is connected to a carbon atom, which in turn is bonded to other atoms or groups. --- **Answer Choices:** A. Four sigma bonds B. Three sigma bonds, one pi bond and no nonbonding electrons C. Two sigma bonds, two pi bonds and no nonbonding electrons D. Two pi bonds and four nonbonding electrons E. One sigma bond and six nonbonding electrons --- Please select the correct answer from the above options and proceed with your solution. **Note:** Understanding electron configurations and bonding types (sigma and pi bonds, and nonbonding electrons) will aid in identifying the correct bonding type for the chlorine atom in this structure. --- **Detailed Explanation:** To answer this question, recall the following: - **Sigma (σ) Bonds:** These are single covalent bonds formed from head-on overlapping of atomic orbitals. - **Pi (π) Bonds:** These are additional bonds in double and triple bonds, formed from the side-to-side overlapping of p orbitals. - **Nonbonding Electrons (Lone Pairs):** Electrons that are not involved in bonding but reside on an atom. Use this foundational knowledge to determine how chlorine bonds in this structure, considering it typically forms one sigma bond with its connected carbon and has three pairs of nonbonding electrons. --- By solving this question, you will enhance your understanding of bonding structures in organic compounds and the behavior of chlorinated hydrocarbons. --- For further reading and detailed examples, refer to our modules on **Covalent Bonding** and **Molecular Geometry**. ---
**Educational Content on Hybridization in Organic Chemistry**

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**Question 20.c of 24**

**Prompt:**
Describe the structure, bonding, and properties of the organic functional group provided in the questions below.
  
Identify the correct hybridization of the circled chlorine atom in this structure.

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**Explanation of the Image:**

The image depicts a molecular structure where a chlorine atom (Cl) is bonded to a carbon atom. This chlorine atom, denoted by the symbol "Cl" and circled for emphasis, is part of a long hydrocarbon chain. Additionally, a hydrogen atom (H) is bonded to the same carbon atom. The carbon atoms are represented by the vertices and end of the zigzag line, which is a common representation in organic chemistry to simplify the depiction of carbon chains.

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**Multiple Choice Options for Hybridization:**

A) sp

B) sp²

C) sp³

D) sp⁴

E) sp³d²

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**Details of Hybridization:**

In organic chemistry, hybridization describes the mixing of atomic orbitals to form new hybrid orbitals suitable for the pairing of electrons to form chemical bonds. The type of hybridization depends on the number of regions of electron density around an atom (i.e., single bonds, double bonds, lone pairs, etc.).

Given that chlorine typically forms one single bond and it has three lone pairs of electrons, the hybridization also includes these lone pairs. Therefore, the chlorine atom in the provided structure is likely to be sp³ hybridized.

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**Correct Answer:**

C) sp³

This hybridization is consistent with the bonding and lone pair arrangement of chlorine when it is bonded to a single carbon atom in an organic molecule.

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**Conclusion:**

Understanding hybridization is crucial for determining the geometry and reactivity of molecules. By identifying the hybridization state of atoms within molecules, chemists can predict molecular shapes, bond angles, and chemical behaviors, thereby gaining insights into the compound's properties and potential applications.
Transcribed Image Text:**Educational Content on Hybridization in Organic Chemistry** --- **Question 20.c of 24** **Prompt:** Describe the structure, bonding, and properties of the organic functional group provided in the questions below. Identify the correct hybridization of the circled chlorine atom in this structure. --- **Explanation of the Image:** The image depicts a molecular structure where a chlorine atom (Cl) is bonded to a carbon atom. This chlorine atom, denoted by the symbol "Cl" and circled for emphasis, is part of a long hydrocarbon chain. Additionally, a hydrogen atom (H) is bonded to the same carbon atom. The carbon atoms are represented by the vertices and end of the zigzag line, which is a common representation in organic chemistry to simplify the depiction of carbon chains. --- **Multiple Choice Options for Hybridization:** A) sp B) sp² C) sp³ D) sp⁴ E) sp³d² --- **Details of Hybridization:** In organic chemistry, hybridization describes the mixing of atomic orbitals to form new hybrid orbitals suitable for the pairing of electrons to form chemical bonds. The type of hybridization depends on the number of regions of electron density around an atom (i.e., single bonds, double bonds, lone pairs, etc.). Given that chlorine typically forms one single bond and it has three lone pairs of electrons, the hybridization also includes these lone pairs. Therefore, the chlorine atom in the provided structure is likely to be sp³ hybridized. --- **Correct Answer:** C) sp³ This hybridization is consistent with the bonding and lone pair arrangement of chlorine when it is bonded to a single carbon atom in an organic molecule. --- **Conclusion:** Understanding hybridization is crucial for determining the geometry and reactivity of molecules. By identifying the hybridization state of atoms within molecules, chemists can predict molecular shapes, bond angles, and chemical behaviors, thereby gaining insights into the compound's properties and potential applications.
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