H C 14. What t values form the boundaries of the critical region for a two-tailed test using a sample of n=9 scores and an alpha level of .05? a. t=±1.860 b. t ±1.833 t = ±2.306 d. t = ±2.262 n-1 9-1=8 Open Questions 1. Research results suggest that children with ADHD tend to watch more TV than children who are not diagnosed with the disorder. To examine this relationship, a researcher obtains a random sample of n=36 children, 8 to 12 years old, who have been diagnosed with ADHD. Each child is asked to keep a journal recording how much time each day is spent watching TV. The average for the sample is M = 4.9 hours. It is known that the average time for the general population of 8 to 12 year-old children is u = 4.1 hours per day, with s = 1.8. a. Are the data sufficient to conclude that the time spent watching TV is significantly different for children with ADHD than for children without the disorder? Use a two- tailed test with a = .05. 0.05=0.025 2 =1.96 -1.96 +367 1.96 Z=M-49-4.9-4.L=0.8=2.67 S/N 18/136 0.3 ↓ Null- no difference in Watching TV. b. If the researcher had used a sample of n = 9 children and obtained the same sample mean, would the results be sufficient to reject HO? HINT: changing n changes the df as well as the estimated standard error, so you need to recalculate t A local business, Treehouse Inc., has gained a reputation lately for misogyny and sexism omplaining about being denied promotions because Langued
H C 14. What t values form the boundaries of the critical region for a two-tailed test using a sample of n=9 scores and an alpha level of .05? a. t=±1.860 b. t ±1.833 t = ±2.306 d. t = ±2.262 n-1 9-1=8 Open Questions 1. Research results suggest that children with ADHD tend to watch more TV than children who are not diagnosed with the disorder. To examine this relationship, a researcher obtains a random sample of n=36 children, 8 to 12 years old, who have been diagnosed with ADHD. Each child is asked to keep a journal recording how much time each day is spent watching TV. The average for the sample is M = 4.9 hours. It is known that the average time for the general population of 8 to 12 year-old children is u = 4.1 hours per day, with s = 1.8. a. Are the data sufficient to conclude that the time spent watching TV is significantly different for children with ADHD than for children without the disorder? Use a two- tailed test with a = .05. 0.05=0.025 2 =1.96 -1.96 +367 1.96 Z=M-49-4.9-4.L=0.8=2.67 S/N 18/136 0.3 ↓ Null- no difference in Watching TV. b. If the researcher had used a sample of n = 9 children and obtained the same sample mean, would the results be sufficient to reject HO? HINT: changing n changes the df as well as the estimated standard error, so you need to recalculate t A local business, Treehouse Inc., has gained a reputation lately for misogyny and sexism omplaining about being denied promotions because Langued
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
Related questions
Question
Open question #1 (letter b)::
Explain throughly please
Transcribed Image Text:H
C 14. What t values form the boundaries of the critical region for a two-tailed test using a
sample of n=9 scores and an alpha level of .05?
a. t=±1.860
b. t
±1.833
t = ±2.306
d. t = ±2.262
n-1
9-1=8
Open Questions
1. Research results suggest that children with ADHD tend to watch more TV than children who
are not diagnosed with the disorder. To examine this relationship, a researcher obtains a random
sample of n=36 children, 8 to 12 years old, who have been diagnosed with ADHD. Each child
is asked to keep a journal recording how much time each day is spent watching TV. The average
for the sample is M = 4.9 hours. It is known that the average time for the general population of 8
to 12 year-old children is u = 4.1 hours per day, with s = 1.8.
a. Are the data sufficient to conclude that the time spent watching TV is significantly
different for children with ADHD than for children without the disorder? Use a two-
tailed test with a = .05. 0.05=0.025
2
=1.96
-1.96
+367
1.96
Z=M-49-4.9-4.L=0.8=2.67
S/N
18/136
0.3
↓
Null- no difference
in Watching TV.
b. If the researcher had used a sample of n = 9 children and obtained the same sample
mean, would the results be sufficient to reject HO?
HINT: changing n changes the df as well as the estimated standard error, so you need to
recalculate t
A local business, Treehouse Inc., has gained a reputation lately for misogyny and sexism
omplaining about being denied promotions because
Langued
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