H (b) This compound does not have an acidic proton, and is expected to have a pKa above 20. H (c) Deprotonation (of the highlighted proton) results in a resonance-stabilized enolate ion. Therefore, the highlighted proton is the most acidic proton (with a pKa just below 20), because its removal leads to a stabilized conjugate base. سلم H (d) Deprotonation (of the highlighted proton) results in a resonance-stabilized conjugate base (a stabilized enolate). Therefore, the highlighted proton is the most acidic proton (with a pKa below 20), because its removal leads to the most stable conjugate base possible. (e) Deprotonation (of the highlighted proton) results in an alkoxide ion. As such, the compound below is expected to have a pKa lower than 20 (see the pKa table at the beginning of the textbook). H

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Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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I understand how to identify an acidic proton, but I dont understand how its determined wether thse compounds have a pka below or above 20. (the instructions were to identify the acidic proton in each product and determine which the compounds would have a pka of less than 20. 

(b) This compound does not have an acidic proton, and is expected to have a pKa above 20.

(c) Deprotonation (of the highlighted proton) results in a resonance-stabilized enolate ion. Therefore, the highlighted proton is the most acidic proton (with a pKa just below 20), because its removal leads to a stabilized conjugate base.

(d) Deprotonation (of the highlighted proton) results in a resonance-stabilized conjugate base (a stabilized enolate). Therefore, the highlighted proton is the most acidic proton (with a pKa below 20), because its removal leads to the most stable conjugate base possible.

(e) Deprotonation (of the highlighted proton) results in an alkoxide ion. As such, the compound below is expected to have a pKa lower than 20 (see the pKa table at the beginning of the textbook).
Transcribed Image Text:(b) This compound does not have an acidic proton, and is expected to have a pKa above 20. (c) Deprotonation (of the highlighted proton) results in a resonance-stabilized enolate ion. Therefore, the highlighted proton is the most acidic proton (with a pKa just below 20), because its removal leads to a stabilized conjugate base. (d) Deprotonation (of the highlighted proton) results in a resonance-stabilized conjugate base (a stabilized enolate). Therefore, the highlighted proton is the most acidic proton (with a pKa below 20), because its removal leads to the most stable conjugate base possible. (e) Deprotonation (of the highlighted proton) results in an alkoxide ion. As such, the compound below is expected to have a pKa lower than 20 (see the pKa table at the beginning of the textbook).
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