H 4 ft -4 ft- 3000 lb 1000 lb B K 4 ft Determine the magnitude of the force (in Ibs) in member CJ. Include the negative sign if the mem ompression. 6 ft 6 ft - 6 ft

Q: 300 mm 30° 300 mm 300 mm Can some one please label the projection of F and the rest of the…

A: Solution: The force vector F and uOA:

Q: Which of the following most nearly gives the internal degree of indeterminacy? 102 34 28 84 Next ▸ ◄…

A: Is question is from structural analysis in this question a frame given and we are asked to find out…

Q: 4m 2m 2 m 4m 2 m

A: Find centroid of given section

Q: Provide the sectional front view, looking at the direction X, draw the top view, and left-side view…

A:

Q: Prove that: Y = (Gs+ eS;' Yw 1+e

A:

Q: 150 mm Locate the centroid of the coloured area. 50 mm 100 mm 100 mm

A: Marking points over figure- A, B, C, D, E, F In the fig three shapes can be observed clearly- 1.…

Q: 4x = y2 = 2 m

A:

Q: entification: Classify the following beams, frames, and/or trusses as statically determinate,…

A: As per guidelines we need to answer only first thre subparts of question so please repost rest…

Q: 4. Locate the centroid of the shaded area in the figure. y 3cm 6cm 4cm 8cm 9cm 4cm X

A:

Q: y(V) – y = 0 1. y" – 10y' + 29y = 0 2. %3D

A:

Q: e two graphical representations of Mohr’s Circle by hand.

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Q: 5 pie 10 pie A 15 pie G K 80* 100* 120k 6 por 30 pie 180 pie- %3D

A:

Q: Q3. Determine the plastic moment Mp of the cross sections shown, assuming the material to be…

A:

Q: Determine the location of the centroidal x an y of the figure shown.

A: The portion which is cut out needs to be subtracted.

Q: but I nee

A: Draw the figure Consider a differential element of size dy

Q: y=(x^2+2x+1)(x-4)

A: The given equation is: y=x2+2x+1x-4 Adopt substitution method for determining the roots of the given…

Q: Flow and spacing are inversely related O True O False

A: State true or false Flow and spacing are inversely related

Q: find the x bar at the location of centroid along y axis

A: To find x bar

Q: 35 R13, R8 42 12.5 20 R8 R9 15 34 26 25 44 17 OL 91 12

A: Handmade drawings are attached herewith.  Actual scale drawings files cannot be attached here like…

Q: E = 29x 1.' ksi Í 6odiut

A: 1. Determine the fixed end moments FEM for span with udl=wl212FEM for span with point load at centre…

Q: Recall we applied the trapezoidal rule to determine the area of the shape given.

A: Solution;

Q: 5-3[(4x-y)+2y]

A: The given expression is,

Q: The moment diagram by parts are base on the moment diagram of O Fully restrained beam O Cantilever…

A: Moment diagrams by parts is a method to solve the determinate beam and find reactions in beam.

Q: Find the x-coordinate of the centroid in 120 mm mm. - 60 mm - 40 mm 80 mm 60 mm

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Q: Problem 6.2. The undeformed and deformed outline of a material element are as shown in the figure…

A: Consider the diagram as shown below. Now. And,

Q: Find the derivation 4. y = x? sin x + 2x cos x – 2sin x

A:

Q: 112 тm К30 тm ->- 30 тm -+30 тm ->-30 mт -> Рart a) Determine the moment of inertia of the shaded…

A:

Q: Find the centroid.

A:

Q: \frac{1}{4}+\frac{1}{8}

A: To find:- 14+18

Q: Find the centroid of the following cross-sections and planes.

A: Centroid is = (0, 9.427 in)Explanation:Step 1: Calculation for centroid of given section.Thanks.

Q: 100 N 100 N 100 100 150 250

A:

Q: Degree of external as well as static indeterminacy

A: Given :                         Number of members, m = 7Number of joints, j = 8Number of external…

Q: po A - W XX '1

A:

Q: Determine the degree of indeterminacy for each of the following structures:

A:

Q: y | 12 kips 48 kip • ft D A B 4 ft- 4 ft 4 ft FIG. P4.16

A:

Q: Determine external as well as internal indeterminacy

A: Given data : Number of member (m)=15Number of Joint (J)=10Number of external support reaction…

Q: the coordinates of the centroid of the shaded areas

A: To find the coordinates of the centroids

Q: What is the x and y - coordinate of the centroid.

A:

Q: Solve for x 5-5x>7x+16

A: Given: 5-5x>7x+16

Types of Composite

Composite materials are formed by merging two components that have different chemical and physical properties. The merged output is termed as a composite, whose properties are completely different from the individual components. Composite materials also have better strength than the individual components.Composite materials usually have two main parts, reinforcement material, and matrix material. The matrix material acts as a binder and surrounds the fiber of another material that bears a much higher strength. This material is known as the reinforcement material. The matrix materials are usually high-strength additives resins, while the fibers of the reinforced material can be random, oriented, and in a mat format.Composite materials are also known as fiber-reinforced composite polymers because they are composed of the polymer matrix which is reinforced to laboratory-created fibers or naturally occurring fibers, such as glass fibers, carbon fibers, or aramid fibers. Under the application of external loads, the matrix material absorbs and transfers the loads to the fibers, these fibers in return provide good compressive strength, tensile strength, and stiffness to the fiber-reinforced composite materials.Depending upon the matrix and the reinforcement material, different properties can be induced to the fiber-reinforced composite materials, including good corrosion resistance properties. The most common matrix material is the resin while the glass fibers act as the reinforcement material. Strong fibers provide strength and stiffness to the composite materials while, a soft and flexible resin provides shape to the composite materials.