Guidance Missile System A missile guidance system has nine fail-safe components. The probability of each failing is 0.40. Assume the variable is binomial. Find the following probabilities. Round your answers to at least four decimal places. Part: 0 / 4 Part 1 of 4 (a) Exactly six will fail. P(exactly six will fail) =
Guidance Missile System A missile guidance system has nine fail-safe components. The probability of each failing is 0.40. Assume the variable is binomial. Find the following probabilities. Round your answers to at least four decimal places. Part: 0 / 4 Part 1 of 4 (a) Exactly six will fail. P(exactly six will fail) =
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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![### Guidance Missile System
A missile guidance system has nine fail-safe components. The probability of each failing is 0.40. Assume the variable is binomial. Find the following probabilities. Round your answers to at least four decimal places.
#### Part: 0 / 4
---
#### Part 1 of 4
(a) Exactly six will fail.
\[ P(\text{exactly six will fail}) = \]
---
In this problem, we are dealing with a binomial distribution where we need to determine the probability of exactly six out of nine components failing, given that each component has a 0.40 chance of failure. To solve this, you would typically use the formula for binomial probability:
\[ P(X = k) = \binom{n}{k} p^k (1-p)^{n-k} \]
where:
- \( n \) is the number of trials (components),
- \( k \) is the number of successes (failures in this context),
- \( p \) is the probability of success (failure),
- \( \binom{n}{k} \) is the binomial coefficient.
Graph or Diagram Explanation:
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Transcribed Image Text:### Guidance Missile System
A missile guidance system has nine fail-safe components. The probability of each failing is 0.40. Assume the variable is binomial. Find the following probabilities. Round your answers to at least four decimal places.
#### Part: 0 / 4
---
#### Part 1 of 4
(a) Exactly six will fail.
\[ P(\text{exactly six will fail}) = \]
---
In this problem, we are dealing with a binomial distribution where we need to determine the probability of exactly six out of nine components failing, given that each component has a 0.40 chance of failure. To solve this, you would typically use the formula for binomial probability:
\[ P(X = k) = \binom{n}{k} p^k (1-p)^{n-k} \]
where:
- \( n \) is the number of trials (components),
- \( k \) is the number of successes (failures in this context),
- \( p \) is the probability of success (failure),
- \( \binom{n}{k} \) is the binomial coefficient.
Graph or Diagram Explanation:
There are no graphs or diagrams provided in this particular question.
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