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Guess the value of the limit (if it exists) by evaluating the function at the given numbers. (It is suggested that you report answers accurate to at least six decimal places.) cos(6x)-cos(52) Let f(x) = We want to find the limit lim Z-0 cos(6x) - cos(5x) 22 Start by calculating the values of the function for the inputs listed in this table. I f(x) 0.2 0.1 0.05 0.01 0.001 0.0001 0.00001 Based on the values in this table, it appears lim 2-40 cos(62) cos(52)

Guess the value of the limit (if it exists) by evaluating the function at the given numbers. (It is suggested that you report answers accurate to at least six decimal places.) cos(6x)-cos(52) Let f(x) = We want to find the limit lim Z-0 cos(6x) - cos(5x) 22 Start by calculating the values of the function for the inputs listed in this table. I f(x) 0.2 0.1 0.05 0.01 0.001 0.0001 0.00001 Based on the values in this table, it appears lim 2-40 cos(62) cos(52)

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Guess the value of the limit (if it exists) by evaluating the function at the given numbers. (It is suggested that you report answers accurate to at least six decimal places.) Let f(x) = cos(6x) - cos(5x) x² We want to find the limit lim 1-0 cos(6x) - cos(5x) x² Start by calculating the values of the function for the inputs listed in this table. f(x) 0.2 0.1 0.05 0.01 0.001 0.0001 0.00001 Based on the values in this table, it appears lim cos(62)-cos(52)
Transcribed Image Text:Guess the value of the limit (if it exists) by evaluating the function at the given numbers. (It is suggested that you report answers accurate to at least six decimal places.) Let f(x) = cos(6x) - cos(5x) x² We want to find the limit lim 1-0 cos(6x) - cos(5x) x² Start by calculating the values of the function for the inputs listed in this table. f(x) 0.2 0.1 0.05 0.01 0.001 0.0001 0.00001 Based on the values in this table, it appears lim cos(62)-cos(52)
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