Grey-Sloan Hospital's location has an elevation of 673.51 meters while Seattle's Station 19 Fire Station has an elevation of 616.62 meters. If the Space Needle (Elev. 631.91 meters) is located 14 km from Grey-Sloan & 11 km from Station 19,compute the OBSTRUCTION or CLEARANCE (in meters) of the line of sight at the Space Needle when observing Station 19 from Grey-Sloan Hospital. Consider curvature and refraction.Round off to three decimal places. Input the magnitude only.

Measurement is the process of determining the height of one level relative to another. It is used to…

Answered: Grey-Sloan Hospital's location has an…

Traffic and Highway Engineering

5th Edition

ISBN:9781305156241

Author:Garber, Nicholas J.

Publisher:Garber, Nicholas J.

Chapter14: Highway Surveys And Location

Section: Chapter Questions

Problem 12P

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Similar questions

Calculate the combined curvature and refraction (in m) for a distance correction for of 2 km.
A trigonometric leveling was employed to determine the elevation of CGY-2022. The instrument was set-up at CGY-2021 and observed that the inclined distance is 1011.02. During measurement it was found out that CGY-2022 is lower that CGY-2021 and that the observed angle was 10°04'01" and elevation of CGY-2021 is 96.12 m. Determine the Earth's curvature and Atmospheric refraction correction with the assumption that height of instrument is equal to the rod reading. Select the correct response: 0.02 0.07 0.20 0.70
The upper and lower stadia hair readings on a stadia rod held at station B were observed as 3.50 and 1.00 m, respectively, with the use of a transit with an internal focusing telescope and having a stadia interval factor of 99.5. The height of the instrument above station A is 1.45 m, and the rod reading is taken at 2.25 m. Determine the horizontal distance between points A and B, and the elevation of point B, if the elevation of point A is 155.54 m, above mean sea level.
The sum of negative departures exceeds that of the positive departures by 0.47 meter. The sum of the positive latitude exceeds that of the negative by 0.81 meter. Linear error of closure is: O 0.74 m O 0.62 m O 0.82 m O 0.94 m
A vertical angle is measured to a signal mounted on top of a tower. With the transit telescope in direct position, the reading on the circle is +22 (deg) 32 (min). If the reading on the circle is +22 (deg) 38 (min) with the telescope in the reversed position. The index correction is?
The sum of positive departures exceeds that of the negative departures by 0.47 meter. The sum of the negative latitude exceeds that of the positive by 0.67 meter. Linear error of closure is: O 0.82 m O 0.94 m O 0.62 m O 0.74 m
TRIGONOMETRIC LEVELING. A vertical angle of -12°25’ is measured to the top of a water tank from an instrument set up on a hill 585.00 meters away from it. The telescope of the instrument is 1.45 m above the ground whose elevation is 462.73 m. Making due allowance for the earth’s curvature and atmospheric refraction, determine the elevation of the base of the water tank is the tank is 32.0 m high. with complete solution adn figure of the said problem
Surveying question
Two points, A and B, are 3,134.50 meters apart. From a third point, C, on the line between A and B, and 1,992.25 meters from A, the measured vertical angle to A is +35°28' and that to B is -15°14'. Considering the effect of curvature and atmospheric refraction, A. If the height of instrument above the ground at C is 1.15 m, determine the difference in elevation between A and the ground point C. B. Determine the difference in elevation between B and the ground point C. C. Determine the difference in elevation between A and B. Express the answers in 3 decimal places.
In trignometric leveling, correction for curvature and refraction is negligible if O the slope distance between two points is less than 1000 ft O the slope distance between two points is less than 100 m O the horizontal distance between two points is less than 1000 ft O the horizontal distance between two points is less than 100 m
Determine the combined effect of curvature and refraction on level sights of 30, 50, 100, 250, 300, 500, 1000, and 2000 m.
A) A back sight of 3.0545 m is taken on a point 50 m from the level. A fore sight 2.1604 m is taken on a point 250 m from the level. Compute the correct difference in level (height) between the two points, taking into effect: (i) The Earth curvature only. (ii) The Earth curvature and refraction together. (Note: if you do not know the earth curvature correction, you can derive it. Use earth radius = 6370 km, there is no mark allocated for that. All the results must be given to 4 decimals) 50.0 m 250.0 m

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