in Pal> Q. 6. The nominal power of a shunt generator is 30 kW. The nominaloutputbrasistoltage of the generator is 240 V. The shunt field windingresistance is 50 2. The armature resistance is 0.1 0. The operating pointparameters are given as the rotor emf 255 terminal voltage 240 V,and the mechanical power loss 1232 W. So,(a) Determine the output power and the efficiency.(b) If the brush voltage drop is 1.2 V, determine the output power and theefficiency.**Do not forg to draw the equivalent circuit first.Prahin Jiskanan, PhD

In this question, we need to determine the output power and efficiency of the DC generator.…

> Q. 6. The nomin I power of a shunt generator is 30 kW. The no output voltage of the generator is 240 V. The shunt field resistance is 50 2. The armature resistance is 0.1 wine are given as the rotor emf 255 V Toraparameters a and the mechanical power loss 1232 W. the winding operating point 55, the terminal voltage 240 V, (a) Determine the output power and the efficiency. (b) If the brush voltage drop 1.2 V, determine the output power and the efficiency. Jiskan *Do not forget to draw the equivalent circuit first. PhD

> Q. 6. The nomin I power of a shunt generator is 30 kW. The no output voltage of the generator is 240 V. The shunt field resistance is 50 2. The armature resistance is 0.1 wine are given as the rotor emf 255 V Toraparameters a and the mechanical power loss 1232 W. the winding operating point 55, the terminal voltage 240 V, (a) Determine the output power and the efficiency. (b) If the brush voltage drop 1.2 V, determine the output power and the efficiency. Jiskan *Do not forget to draw the equivalent circuit first. PhD

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

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