> amount; 'cin' does not name a type; did you mean 'sin'? 4 cout << endl; 'cout' does not name a type 5 int numBills1 = (int) (amount / 20.0); if (numBills1 20.0< amount) { expected unqualified-id before if numBills1++; 7 8} 9 cout << "How much will Jane be spending? "; 'cout' does not name a type 18 cin >> amount; 'cin' does not name a type; did you mean 'sin'? 11 cout << endl; 'cout' does not name a type 12 int numBills2 = (int) (amount / 20.0); 13 if (numBills2 * 20.0< amount) { expected unqualified-id before 'if' numBills2++; 14 15 } 16 cout << "John needs " << numBills1 << "bills" << endl; 'cout' does not name a type 17 cout << "Jane needs " << numBills2 << " bills" << endl; 'cout' does not name a type Function: Write a C++ function as described, not a complete program. X X X X X X X X X X X

Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
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Question

correct the code

<percentageGrade
You are working on problem set: PS4
→ spending ♡
Language/Type:
Related Links:
Pause)
i
C++ if/else input redundancy console input
string
Main Page → Exercises → PS4 → C++→Solve an Exercise
The following code is poorly structured. Rewrite it so that it has a better structure and avoids redundancy. To help
eliminate redundancy, convert the code into a function named spending that accepts as its parameter a string for
a single person's name, and prints the appropriate information about that person's bills. Your function could be
called twice (once for John and once for Jane) to replicate the original code's behavior.
1 cout << "How much will John be spending? ";
problem context error: expected function, but found bare code
'cout' does not name a type
2 double amount;
3 cin >> amount;
'cin' does not name a type; did you mean 'sin'?
4 cout << endl;
!!'cout' does not name a type
5 int numBills1 = (int) (amount / 20.0);
6 if (numBills1 * 20.0 < amount) {
expected unqualified-id before 'if'
numBills1++;
7
8}
9 cout << "How much will Jane be spending? ";
'cout' does not name a type
10 cin >> amount;
'cin' does not name a type; did you mean 'sin'?
11 cout << endl;
'cout' does not name a type
12 int numBills2 = (int) (amount / 20.0);
13 if (numBills2 * 20.0< amount) {
expected unqualified-id before 'if'
numBills2++;
14
15 }
16 cout << "John needs " << numBills1 << " bills" << endl;
'cout' does not name a type
17 cout << "Jane needs " << numBills2 << " bills" << endl;
'cout' does not name a type
Function: Write a C++ function as described, not a complete program.
x x
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X
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Transcribed Image Text:<percentageGrade You are working on problem set: PS4 → spending ♡ Language/Type: Related Links: Pause) i C++ if/else input redundancy console input string Main Page → Exercises → PS4 → C++→Solve an Exercise The following code is poorly structured. Rewrite it so that it has a better structure and avoids redundancy. To help eliminate redundancy, convert the code into a function named spending that accepts as its parameter a string for a single person's name, and prints the appropriate information about that person's bills. Your function could be called twice (once for John and once for Jane) to replicate the original code's behavior. 1 cout << "How much will John be spending? "; problem context error: expected function, but found bare code 'cout' does not name a type 2 double amount; 3 cin >> amount; 'cin' does not name a type; did you mean 'sin'? 4 cout << endl; !!'cout' does not name a type 5 int numBills1 = (int) (amount / 20.0); 6 if (numBills1 * 20.0 < amount) { expected unqualified-id before 'if' numBills1++; 7 8} 9 cout << "How much will Jane be spending? "; 'cout' does not name a type 10 cin >> amount; 'cin' does not name a type; did you mean 'sin'? 11 cout << endl; 'cout' does not name a type 12 int numBills2 = (int) (amount / 20.0); 13 if (numBills2 * 20.0< amount) { expected unqualified-id before 'if' numBills2++; 14 15 } 16 cout << "John needs " << numBills1 << " bills" << endl; 'cout' does not name a type 17 cout << "Jane needs " << numBills2 << " bills" << endl; 'cout' does not name a type Function: Write a C++ function as described, not a complete program. x x X X X X X X X X X X X
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