Graphical Solution Force Mass (kg) Force (N) Direction F1 0.100 20.0° F2 0.200 900" Resultant FRI Analytical Solution Fore Mass (kg) Force (N) Direction x-component у сотропеnt 0.100 20.0" F2 0.200 90.0" Resultant FRI

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2. One pulley is placed at the 20.0° mark on the force table with 0.100 kg (including the mass holder) on
the end of the string. The other pulley is placed at 90.0° with a suspended mass of 0.200 kg. Determine
the value of blank spaces.
Graphical Solution
Force
Mass (kg)
Force (N)
Direction
F1
0.100
20.0°
F2
0.200
90.0°
Resultant FRI
Analytical Solution
Force
Mass (kg)
Force (N)
Direction
x-component
у сотропеnt
F1
0.100
20.0°
F2
0.200
90.0"
Resultant FR1
Transcribed Image Text:2. One pulley is placed at the 20.0° mark on the force table with 0.100 kg (including the mass holder) on the end of the string. The other pulley is placed at 90.0° with a suspended mass of 0.200 kg. Determine the value of blank spaces. Graphical Solution Force Mass (kg) Force (N) Direction F1 0.100 20.0° F2 0.200 90.0° Resultant FRI Analytical Solution Force Mass (kg) Force (N) Direction x-component у сотропеnt F1 0.100 20.0° F2 0.200 90.0" Resultant FR1
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