GRAPHIC 61+200 FØ13," (75 HP) -70% 75% SCALE 80% 82% 83% Ø12%" (60 HP) 84% 83% 82% 80% 46+150 Ø12%" (50 HP) 75% Ø11%" (40 HP) 70% 65% 31+100 Ø10%" (30 HP) 100 BHF 75 BHP 60 ВНР 15+50 50 BHP 40 ВHP 30 ВНР NPSHr GALLONS PER MINUTE LITERS PER MINUTE Refer to the system curve drawn on this pump curve. If the pump is to move 1080 gpm, what size impeller should be specified? O 10 7/16" pump impeller O 11 7/16" pump impeller O 12 3/16" pump impeller O 12 3/4" pump impeller 13 1/," pump impeller 1136+300 2271+600 006+20E 4543+1200 5678+1500 6414+1800 7949+2100 9085 2400

Q: Column2 700mm 1 3m Beam2 4 3. 700mm+ Column1- 3 3 1 +350+ . 4 350 15. 2 2 2 Beam3 5m Beam1 1 11 4m…

A: Volume of BEAM 1= (4-0.35/2-1.050/2)*0.35*0.45= 3.3*0.35*0.45= 0.51975= 0.52 m3 Volume of BEAM 2=…

Q: 60 kips 20 EX/ Analysis all member C G 20' F 60 kips 20 15' 30 kips 15'

A: All data is given in the figure belowneed to findforces in all member

Q: The beam cross sections shown are symmetric about the x and y axes. Determine the area moments of…

A: Given data,beam cross section is given top flange width =140mmheight=250 mmthickness of web =6…

Q: free-body diagram. Yo

A:

Q: 200 N 53° A 36° 1.5 189 N 42 kN/m 3 В 4 3

A: When we are calculating the moment due to udl or Uvl we calculate it as  Force acting /m length ×…

Q: Explain what a kinematic contraint is.

A: The constraints between the rigid bodies are called as kinematic constraints. Due to kinematic…

Q: Identify and circle others Simply Supported Beam and continous Beam at structural drawing

A: To Identify Simply Supported Beam and continuous Beam at structural drawing, other than that which…

Q: Can you do it fast

A:

Q: Problem 3 Complete 5.130 from the course text. 5/130 Determine the shear force V and bending moment…

A:

Q: 152 x 152 x 23 UC Frame Beam Diagram 28.2KN Self Load 805N 28.2KN 2.0m Ra 75 3.5m Pulley and shaft…

A: In Both frames, deflection is determined using Macaulay's method. The steps to determine deflections…

Q: Column2 3m 700mm+ 1 Column1- 3 Beam2 4 3 A 700mm+ 3 1 4 +350 + P 3 1 350. 2 2 2 Beam3 5m Beam1 1 2…

A: Quantities Beam 1 Beam 2 Beam 3 Length (m) 3.3  2.475 4.125  Width (m) 0.35 0.35 0.35 Depth…

Q: 16-11.828⁰ 9-2 9-5.828¹ 10.342 8x8 POST PIO 12-11.342* 6-5.143* TT 8x12 RAFTER P109 8x8 POST P102…

A: free body diagram of the bottom chord

Q: -30- 15 Compute I, and I, for the plane region. 12.5 45 10 40 Dimensions in mm

A: Moment of inertia about X-axis:            Ix = 12.5x7033+27.5x1033+17.5x15312+17.5x15x70-7.52 Or,…

Q: METERS | FEET 76-250 61-200-013½" (75 HP) 1 Ø12%" (60 HP) THE Ø12" (50 HP) 46-150 al Ø11" (40 HP)…

A: From the graph, the red line represents the intersection. For 11716'' impellers, the horsepower is…

Q: Use Factor method in solving this problem. Details are already provided in the drawing

A: Beam- 400×500

Length and Length related Variables

Length can de defined as the measurement or extent of physical quantities or objects from one terminal to another terminal. Stone age humans used finger length, step length, and so on to measure the size or displacement of an object. Nowadays, depending on how precise the measurement requires to be and the object’s size is measured, we use measuring devices for measurements like rulers and steel tape. Most people have used a ruler or tape measure to measure a particular distance or the size of an object. For more precise measurements of tiny objects, the development of measurement tools such as the Vernier caliper, which permits us to measure dimensions within 1/1000 of an inch. In the last few decades, electronic distance measuring instruments (EDMI) have been implemented that permit us to measure distances from a few feet to many miles with reasonable accuracy.