Graph the total resultant vectors of all the 4 forces and angles, The Data is listed in the graph. Static Equilibrium with four forces (All four angles cannot be 90 degrees)Mass (Kg) F=9.8 m/s?x massAngle indegreesF, = FcoseFy = F sineForce 10.085kg0.86 N120.81-0.73Force 20.055kg0.539 N670.2100.17Force 30.106kg1.03 N175-1.0350.50Force 40.075kg0.735 N2750.060.09Sum of x component and y component of each force0.040.03

Name: Graph the total resultant vectors of all the 4 forces and angles, The
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Description: Graph the total resultant vectors of all the 4 forces and angles, The Data is listed in the graph. Static Equilibrium with four forces (All four angles cannot be 90 degrees)Mass (Kg) F=9.8 m/s?x massAngle indegreesF, = FcoseFy = F sineForce 10.085kg0

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ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

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Graph the total resultant vectors of all the 4 forces and angles, The Data is listed in the graph.

Static Equilibrium with four forces (All four angles cannot be 90 degrees)
Mass (Kg) F=9.8 m/s?x mass
Angle in
degrees
F, = Fcose
Fy = F sine
Force 1
0.085kg
0.86 N
12
0.81
-0.73
Force 2
0.055kg
0.539 N
67
0.210
0.17
Force 3
0.106kg
1.03 N
175
-1.035
0.50
Force 4
0.075kg
0.735 N
275
0.06
0.09
Sum of x component and y component of each force
0.04
0.03

Expert Solution

Step 1

We are required to graph the resultant force F.

First, we will find the resultant force by adding the x and y-component of force together, then we will plot it.

$F_{x} = 0.81 + 0.21 - 1.035 + 0.06 + 0.04 F_{x} = 1.12 - 1.035 = 0.085 N F_{y} = - 0.73 + 0.17 + 0.50 + 0.09 + 0.03 F_{y} = 0.06 N$

We deduce here that since both the sums are positive, so the resultant force lies in the first quadrant.

And its direction:

$θ = \tan^{- 1} (\frac{0.06}{0.085}) = 35.2 °$

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