Graph the function by using transformation. Find the domain and the range of the function. f (x)= Vx-3 + 1

Trigonometry (11th Edition)
11th Edition
ISBN:9780134217437
Author:Margaret L. Lial, John Hornsby, David I. Schneider, Callie Daniels
Publisher:Margaret L. Lial, John Hornsby, David I. Schneider, Callie Daniels
Chapter1: Trigonometric Functions
Section: Chapter Questions
Problem 1RE: 1. Give the measures of the complement and the supplement of an angle measuring 35°.
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### Analyzing and Graphing the Function

#### Problem Statement:
Graph the function by using transformation. Find the domain and the range of the function.

\[ f(x) = \sqrt{x - 3} + 1 \]

#### Step-by-Step Solution:

1. **Understanding the Base Function:**
   The base function here is \( \sqrt{x} \), which is a square root function. The basic graph of \( \sqrt{x} \) starts at the origin (0,0) and increases slowly as x increases, forming a curve.

2. **Applying the Transformation:**
   - The given function is \( f(x) = \sqrt{x - 3} + 1 \).
   - The expression inside the square root, \( x - 3 \), indicates a horizontal shift.
   - Specifically, \( x - 3 \) shifts the graph 3 units to the right.
   - The \( +1 \) outside the square root affects the vertical position of the graph, shifting it 1 unit up.

3. **Graphing the Transformed Function:**
   - Start by shifting the graph of \( \sqrt{x} \) 3 units to the right.
   - Then shift the resulting graph 1 unit upwards.
   - Plot some key points for accuracy. For instance, at \( x = 3 \), \( f(3) = \sqrt{3 - 3} + 1 = 0 + 1 = 1 \).
   - Continue plotting points and draw the smooth curve that results from connecting them.

4. **Determining the Domain:**
   - The domain of a function includes all the possible x-values.
   - Since we have a square root function starting from \( x = 3 \), the values under the square root must be non-negative.
   - Therefore, \( x - 3 \geq 0 \implies x \geq 3 \).
   - **Domain:** \( [3, \infty) \)

5. **Determining the Range:**
   - The range of a function includes all the possible y-values.
   - For the transformed function \( f(x) \), when \( x = 3 \), \( f(3) = 1 \).
   - As \( x \) increases, \( f(x) \) also increases because the square root function always yields non-negative results.
   - Thus,
Transcribed Image Text:### Analyzing and Graphing the Function #### Problem Statement: Graph the function by using transformation. Find the domain and the range of the function. \[ f(x) = \sqrt{x - 3} + 1 \] #### Step-by-Step Solution: 1. **Understanding the Base Function:** The base function here is \( \sqrt{x} \), which is a square root function. The basic graph of \( \sqrt{x} \) starts at the origin (0,0) and increases slowly as x increases, forming a curve. 2. **Applying the Transformation:** - The given function is \( f(x) = \sqrt{x - 3} + 1 \). - The expression inside the square root, \( x - 3 \), indicates a horizontal shift. - Specifically, \( x - 3 \) shifts the graph 3 units to the right. - The \( +1 \) outside the square root affects the vertical position of the graph, shifting it 1 unit up. 3. **Graphing the Transformed Function:** - Start by shifting the graph of \( \sqrt{x} \) 3 units to the right. - Then shift the resulting graph 1 unit upwards. - Plot some key points for accuracy. For instance, at \( x = 3 \), \( f(3) = \sqrt{3 - 3} + 1 = 0 + 1 = 1 \). - Continue plotting points and draw the smooth curve that results from connecting them. 4. **Determining the Domain:** - The domain of a function includes all the possible x-values. - Since we have a square root function starting from \( x = 3 \), the values under the square root must be non-negative. - Therefore, \( x - 3 \geq 0 \implies x \geq 3 \). - **Domain:** \( [3, \infty) \) 5. **Determining the Range:** - The range of a function includes all the possible y-values. - For the transformed function \( f(x) \), when \( x = 3 \), \( f(3) = 1 \). - As \( x \) increases, \( f(x) \) also increases because the square root function always yields non-negative results. - Thus,
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