Graph the following quadratic function using its properties. G(x) = - x + 2x + 8

Algebra and Trigonometry (6th Edition)
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ChapterP: Prerequisites: Fundamental Concepts Of Algebra
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Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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**12. Graph the following quadratic function using its properties.**

\[ G(x) = -x^2 + 2x + 8 \]

To graph this quadratic function effectively, we should examine its properties, such as the vertex, axis of symmetry, and intercepts.

- **Vertex**: The vertex can be found using the formula \( x = -\frac{b}{2a} \). For the function \( G(x) = -x^2 + 2x + 8 \), \( a = -1 \) and \( b = 2 \). Solving this gives \( x = -\frac{2}{2(-1)} = 1 \). Substitute back to find \( G(1) = -(1)^2 + 2(1) + 8 = 9 \). Thus, the vertex is at \( (1, 9) \).

- **Axis of Symmetry**: This is the vertical line \( x = 1 \).

- **Intercepts**: The y-intercept is found by evaluating \( G(x) \) at \( x = 0 \): \( G(0) = 8 \). To find the x-intercepts, set \( G(x) \) to zero and solve for \( x \): 
  \[ 0 = -x^2 + 2x + 8 \]
  Solving this quadratic equation gives the points of intersection with the x-axis.

- **Direction**: Since the coefficient of \( x^2 \) is negative, the parabola opens downwards.

By utilizing these properties, the graph of the function can be accurately depicted.
Transcribed Image Text:**12. Graph the following quadratic function using its properties.** \[ G(x) = -x^2 + 2x + 8 \] To graph this quadratic function effectively, we should examine its properties, such as the vertex, axis of symmetry, and intercepts. - **Vertex**: The vertex can be found using the formula \( x = -\frac{b}{2a} \). For the function \( G(x) = -x^2 + 2x + 8 \), \( a = -1 \) and \( b = 2 \). Solving this gives \( x = -\frac{2}{2(-1)} = 1 \). Substitute back to find \( G(1) = -(1)^2 + 2(1) + 8 = 9 \). Thus, the vertex is at \( (1, 9) \). - **Axis of Symmetry**: This is the vertical line \( x = 1 \). - **Intercepts**: The y-intercept is found by evaluating \( G(x) \) at \( x = 0 \): \( G(0) = 8 \). To find the x-intercepts, set \( G(x) \) to zero and solve for \( x \): \[ 0 = -x^2 + 2x + 8 \] Solving this quadratic equation gives the points of intersection with the x-axis. - **Direction**: Since the coefficient of \( x^2 \) is negative, the parabola opens downwards. By utilizing these properties, the graph of the function can be accurately depicted.
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Given,            g(x) = -x2 + 2x + 8

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