Graph the following function and find the area under the curve on the given interval. -2 f(x) = (64-x²)-², [0,4] Use the reduction formula of sec ³u, I sec u du = 1 (sec u tan u + In sec u + tanu) + C, a
Graph the following function and find the area under the curve on the given interval. -2 f(x) = (64-x²)-², [0,4] Use the reduction formula of sec ³u, I sec u du = 1 (sec u tan u + In sec u + tanu) + C, a
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Question
Find the area under the curve
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Graph the following function and find the area under the curve on the given interval.
f(x) = (64-x²)-², [0,4]
Use the reduction formula of sec
c³u₁
с
H
sec u du =
All graphs are shown in a [- 14,14,1] by [-4,4,1] window.
The area under the curve on the given interval is
1
(sec u tan u + In sec u + tan u ) + C, as ne
Q
square units.
75°5](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fa204fb01-1593-427c-b210-f132b42420bd%2F8f3461a2-d852-4e2a-ba75-b2cae8b6cbb7%2F5gkzbs_processed.jpeg&w=3840&q=75)
Transcribed Image Text:K
Graph the following function and find the area under the curve on the given interval.
f(x) = (64-x²)-², [0,4]
Use the reduction formula of sec
c³u₁
с
H
sec u du =
All graphs are shown in a [- 14,14,1] by [-4,4,1] window.
The area under the curve on the given interval is
1
(sec u tan u + In sec u + tan u ) + C, as ne
Q
square units.
75°5
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