21 ### Graphing Inequalities Subject to Nonnegative Restrictions**Problem Statement:**Graph the first inequality subject to the nonnegative restrictions:\[ 18x + 30y \leq 1800, \quad x \geq 0, \quad y \geq 0 \]Use the graphing tool to graph the inequality $ 18x + 30y \leq 1800 $ and the boundary lines representing the nonnegative constraints.**Instructions:**1. Identify the boundary line for the inequality $ 18x + 30y = 1800 $.2. Graph the corresponding inequality $ 18x + 30y \leq 1800 $ ensuring that the region satisfying the inequality is shaded.3. Ensure that the graph includes the constraints $ x \geq 0 $ and $ y \geq 0 $, which restrict the feasible region to the first quadrant.**Graph Analysis:**- The graph shows a grid with the horizontal axis labeled $ x $ and the vertical axis labeled $ y $.- The axes are scaled with intervals marking every 250 units.- The positive quadrants are the focus for this graph due to the nonnegative constraints ($ x \geq 0 $ and $ y \geq 0 $). To graph $ 18x + 30y \leq 1800 $:1. Rewrite the inequality in slope-intercept form if needed, or find the intercepts: - For the $ x $-intercept: Set $ y = 0 $ in $ 18x + 30y = 1800 $ to get $ x = 100 $. - For the $ y $-intercept: Set $ x = 0 $ in $ 18x + 30y = 1800 $ to get $ y = 60 $.2. Plot these intercepts $(100, 0)$ and $(0, 60)$ on the graph.3. Draw the boundary line through these intercepts.4. Shade the region below the line to indicate $ 18x + 30y \leq 1800 $.Remember to consider the nonnegative constraints $ x \geq 0 $ and $ y \geq 0 $, restricting the solution to the first quadrant.**Helpful Hint:**Util

Answered: Image /qna-images/answer/4c6e6936-8665-43cc-8c26-27fb09684a7a.jpg

Graph the first inequality subject to the nonnegative restrictions. 18x + 30y≤ 1800, x ≥ 0, y 20 Use the graphing tool to graph 18x + 30y≤ 1800 and the boundary lines representing the nonnegative constraints. Click to enlarge graph -500 -250 Ay 100- $0 -50 -100- 250 X 500 o Q