Graph of one complete cycle of the equation y = -2- cos(2x- x). Identify the period, amplitude and phase shift for this equation.
Graph of one complete cycle of the equation y = -2- cos(2x- x). Identify the period, amplitude and phase shift for this equation.
Trigonometry (11th Edition)
11th Edition
ISBN:9780134217437
Author:Margaret L. Lial, John Hornsby, David I. Schneider, Callie Daniels
Publisher:Margaret L. Lial, John Hornsby, David I. Schneider, Callie Daniels
Chapter1: Trigonometric Functions
Section: Chapter Questions
Problem 1RE:
1. Give the measures of the complement and the supplement of an angle measuring 35°.
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Can I get help with this? Can you please show me the steps you took to find the answers and such please
![### Graph of one complete cycle of the equation \( y = -2 - \cos(2x - \pi) \).
---
**Identify the period, amplitude and phase shift for this equation.**
---
#### Explanation of the Graph:
The graph shown is a Cartesian plane with the x-axis and y-axis marked. There are no specific plots or curves visible, but it is mentioned that it relates to the trigonometric equation \( y = -2 - \cos(2x - \pi) \).
#### Understanding the Given Equation:
1. **Equation:** \( y = -2 - \cos(2x - \pi) \)
2. **Cosine Function Analysis:**
- The equation is in the form \( y = A + B \cdot \cos(Cx + D) \), where:
- \( A = -2 \)
- \( B = -1 \)
- \( C = 2 \)
- \( D = -\pi \)
3. **Amplitude:**
- Amplitude \( = |B| \)
- Here, the amplitude \( = |-1| = 1 \).
4. **Period:**
- The period \( T \) of the function \( \cos(Cx) \) is given by \( \frac{2\pi}{C} \).
- In this case, \( C = 2 \).
- Therefore, \( T = \frac{2\pi}{2} = \pi \).
5. **Phase Shift:**
- The phase shift \( \phi \) is calculated by solving \( Cx + D = 0 \).
- Here, \( 2x - \pi = 0 \implies x = \frac{\pi}{2} \).
- Therefore, the phase shift is \( \frac{\pi}{2} \).
#### Conclusion:
- **Amplitude:** 1
- **Period:** \( \pi \)
- **Phase Shift:** \( \frac{\pi}{2} \)
The graph would typically plot one full cycle of the cosine function, considering the period and phase shift calculated above. The vertical shift is down 2 units due to the -2 term in the equation.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F87f6c903-7c82-4f0e-8549-b569dd14b65f%2F69f977ac-897d-46f7-a540-201ba54aa110%2Fcmrp3zf.png&w=3840&q=75)
Transcribed Image Text:### Graph of one complete cycle of the equation \( y = -2 - \cos(2x - \pi) \).
---
**Identify the period, amplitude and phase shift for this equation.**
---
#### Explanation of the Graph:
The graph shown is a Cartesian plane with the x-axis and y-axis marked. There are no specific plots or curves visible, but it is mentioned that it relates to the trigonometric equation \( y = -2 - \cos(2x - \pi) \).
#### Understanding the Given Equation:
1. **Equation:** \( y = -2 - \cos(2x - \pi) \)
2. **Cosine Function Analysis:**
- The equation is in the form \( y = A + B \cdot \cos(Cx + D) \), where:
- \( A = -2 \)
- \( B = -1 \)
- \( C = 2 \)
- \( D = -\pi \)
3. **Amplitude:**
- Amplitude \( = |B| \)
- Here, the amplitude \( = |-1| = 1 \).
4. **Period:**
- The period \( T \) of the function \( \cos(Cx) \) is given by \( \frac{2\pi}{C} \).
- In this case, \( C = 2 \).
- Therefore, \( T = \frac{2\pi}{2} = \pi \).
5. **Phase Shift:**
- The phase shift \( \phi \) is calculated by solving \( Cx + D = 0 \).
- Here, \( 2x - \pi = 0 \implies x = \frac{\pi}{2} \).
- Therefore, the phase shift is \( \frac{\pi}{2} \).
#### Conclusion:
- **Amplitude:** 1
- **Period:** \( \pi \)
- **Phase Shift:** \( \frac{\pi}{2} \)
The graph would typically plot one full cycle of the cosine function, considering the period and phase shift calculated above. The vertical shift is down 2 units due to the -2 term in the equation.
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