Grace's bank has a Cerificate of Deposit with an APR of 5% compounded monthly. (a) If Grace deposits $1000 in the account, what will be the value in 5 years? (b) If Grace needs $10,000 in 5 years, how much should she deposit monthly?

Algebra and Trigonometry (6th Edition)
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ChapterP: Prerequisites: Fundamental Concepts Of Algebra
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Grace's bank has a Cerificate of Deposit with an APR of 5% compounded monthly.
(a) If Grace deposits $1000 in the account, what will be the value in 5 years?
(b) If Grace needs $10,000 in 5 years, how much should she deposit monthly? 

**Certificate of Deposit Calculations**

Grace's bank has a Certificate of Deposit (CD) with an Annual Percentage Rate (APR) of 5%, compounded monthly.

**(a) Future Value Calculation:**

*Problem:* If Grace deposits $1000 in the account, what will be the value in 5 years?

To solve this, we use the future value formula for compound interest:

\[ A = P \left(1 + \frac{r}{n}\right)^{nt} \]

where:
- \( A \) = the future value of the investment/loan, including interest.
- \( P \) = the principal investment amount (the initial deposit) = $1000.
- \( r \) = the annual interest rate (decimal) = 0.05.
- \( n \) = the number of times that interest is compounded per year = 12.
- \( t \) = the time the money is invested for in years = 5.

Plugging in the values, we get:

\[ A = 1000 \left(1 + \frac{0.05}{12}\right)^{12 \times 5} \]

**(b) Monthly Deposit Calculation:**

*Problem:* If Grace needs $10,000 in 5 years, how much should she deposit monthly?

To solve this, we use the future value of an annuity formula:

\[ A = P \frac{\left(1 + \frac{r}{n}\right)^{nt} - 1}{\frac{r}{n}} \]

where:
- \( A \) = the future value of the annuity (savings goal) = $10,000.
- \( P \) = the monthly deposit amount.
- \( r \) = the annual interest rate (decimal) = 0.05.
- \( n \) = the number of times the interest is compounded per year = 12.
- \( t \) = the number of years = 5.

Rearranging the formula to solve for \( P \), we get:

\[ P = \frac{A \times \frac{r}{n}}{\left(1 + \frac{r}{n}\right)^{nt} - 1} \]

Substituting the known values:

\[ P = \frac{10000 \times \frac{0.05}{12}}{\left(1 + \frac{
Transcribed Image Text:**Certificate of Deposit Calculations** Grace's bank has a Certificate of Deposit (CD) with an Annual Percentage Rate (APR) of 5%, compounded monthly. **(a) Future Value Calculation:** *Problem:* If Grace deposits $1000 in the account, what will be the value in 5 years? To solve this, we use the future value formula for compound interest: \[ A = P \left(1 + \frac{r}{n}\right)^{nt} \] where: - \( A \) = the future value of the investment/loan, including interest. - \( P \) = the principal investment amount (the initial deposit) = $1000. - \( r \) = the annual interest rate (decimal) = 0.05. - \( n \) = the number of times that interest is compounded per year = 12. - \( t \) = the time the money is invested for in years = 5. Plugging in the values, we get: \[ A = 1000 \left(1 + \frac{0.05}{12}\right)^{12 \times 5} \] **(b) Monthly Deposit Calculation:** *Problem:* If Grace needs $10,000 in 5 years, how much should she deposit monthly? To solve this, we use the future value of an annuity formula: \[ A = P \frac{\left(1 + \frac{r}{n}\right)^{nt} - 1}{\frac{r}{n}} \] where: - \( A \) = the future value of the annuity (savings goal) = $10,000. - \( P \) = the monthly deposit amount. - \( r \) = the annual interest rate (decimal) = 0.05. - \( n \) = the number of times the interest is compounded per year = 12. - \( t \) = the number of years = 5. Rearranging the formula to solve for \( P \), we get: \[ P = \frac{A \times \frac{r}{n}}{\left(1 + \frac{r}{n}\right)^{nt} - 1} \] Substituting the known values: \[ P = \frac{10000 \times \frac{0.05}{12}}{\left(1 + \frac{
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