gold wire carries 24.5 A of current with a drift velocity of 2.5 × 10-3 m/s. Assume there is one free electron per gold atom, and the density of gold is 1.93 × 104 kg/m3. The molecular weight of gold is 196.97 g/mol. Part (a) What is the diameter of this gold wire? d = m
gold wire carries 24.5 A of current with a drift velocity of 2.5 × 10-3 m/s. Assume there is one free electron per gold atom, and the density of gold is 1.93 × 104 kg/m3. The molecular weight of gold is 196.97 g/mol. Part (a) What is the diameter of this gold wire? d = m
College Physics
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Author:Raymond A. Serway, Chris Vuille
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Chapter1: Units, Trigonometry. And Vectors
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Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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A gold wire carries 24.5 A of current with a drift velocity of 2.5 × 10-3 m/s. Assume there is one free electron per gold atom, and the density of gold is 1.93 × 104 kg/m3. The molecular weight of gold is 196.97 g/mol.
Part (a) What is the diameter of this gold wire? | |||||
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Part (b) For the problem above, calculate the resistance of the wire under those conditions. Assume the wire is 3.8 m in length, and the resistivity of gold is 2.44 × 10-8 Ω⋅m. | |||||
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Part (c) How much power is dissipated by this wire? | |||||
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Part (d) If the wire is heated by an additional 89 K (compared to part (a)), what is the new resistance at this increased temperature? The temperature coefficient of resistivity for gold is 3.4 × 10-3 °C-1 | |||||
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Part (e) Under the conditions in part (d), what is the value of the potential for the wire? | |||||
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Part (f) Under the conditions in part (d), how many electrons pass through the wire in 54 s? | |||||
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Expert Solution
Step 1
Given
Current I = 24.5 A
Drift velocity vd = 2.5 × 10-3 m/s
Density =1.93 × 104 kg/m3
Mmolecular weight =196.97 g/mol
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