Part BGold has a face-centered cubic arrangement with a unit cell edge length of 4.08 A . How many moles of gold fit in a goldnanoparticle sheet with a length of 60.1 nm, a width of 20.7 nm , and a thickness of 7.66 nm ?Express your answer with the appropriate units.> View Available Hint(s)µAValueUnitsSubmit< Return to AssignmentProvide FeedbackPearsonson Education Inc. All rights reserved. | Terms of Use | Privacy Policy | Permissions | Contact Us |Show Allutlin..pdfMacBook AirDIIDDF12F11F10F8F7()&789}PY11+ ||

Answered: Image /qna-images/answer/c7be5a44-6a17-4ba3-9de2-ee35cbd94384.jpg

Gold has a face-centered cubic arrangement with a unit cell edge length of 4.08Á. How many moles of gold fit in a gold nanoparticle sheet with a length of 60.1 nm , a width of 20.7 nm , and a thickness of 7.66 nm ? Express your answer with the appropriate units.

Gold has a face-centered cubic arrangement with a unit cell edge length of 4.08Á. How many moles of gold fit in a gold nanoparticle sheet with a length of 60.1 nm , a width of 20.7 nm , and a thickness of 7.66 nm ? Express your answer with the appropriate units.

Physical Chemistry

2nd Edition

ISBN:9781133958437

Author:Ball, David W. (david Warren), BAER, Tomas

Publisher:Ball, David W. (david Warren), BAER, Tomas

Chapter21: The Solid State: Crystals

Section: Chapter Questions

Problem 21.36E: The first two signals from a powdered sample has X rays (=1.47742A) diffracted at angles of 13.48...

See similar textbooks

Related questions

Q: High-density polyethylene (HDPE) is opaque while low-density polyethylene (LDPE) is transparent.…

A: Polyethene is widely used tharmoplastic now a days.Based on molecular structure it can be…

Q: In addition to filling in the blanks below, show all of your work for this problem on paper for…

A: The relationship between atomic radius and edge length for face centered cubic units -

Q: C60 fullerenes crystallizes into a cubic close-packed structure known as fullerite, with a lattice…

Q: Calculate the volume of a unit cell of Nickel in nm3. The volume of unit cell of Nickel is…

Q: Some hypothetical metal has simple cubic crystal structure. If its atomic weight is 67.1 g/mol and…

Q: metallic element, M, has a face-centered cubic lattice structure as a solid. If M has an atomic…

Q: The ionic radii of the Mg21 and 022 ions are 0.86 Å and 1.26 Å, respectively. Given that the…

Q: Lead, Pb, is used in solders as radiation shield. It adopts the face centered cubic unit structure…

A: Given question related to calculation of density of lead.

Q: The density of an unknown metal is 2.64 g/cm3 and its atomic radius is 0.215 nm. It has a…

A: Given density = 2.64g/cm3 r= 0.215nm = 0.215 x 10-7cm a = 4r/2 a = The cube has face centered…

Q: Calcium has a face-centered cubic structure. An edge of its unit cell is 558.8 pm. What is…

A: Since in a face-centred cubic structure, there are atoms present at all the face centres and corners…

Q: If the edge length of the unit cell of Tantalum is 331 pm, calculate the volume of this unit cell in…

Q: Gold has a face-centered cubic arrangement with a unit cell edge length of 4.08 Å. How many moles…

Q: 2) Sodium is a bright, white, soft, and wax-like element dissolves in seawater, crystallizes in rock…

Q: The density of PbSe at room temperature is 8.27 g/cm^3. Calculate the length of an edge of the PbSe…

A: Density of PbSe = 8.27 gcm3

Q: Tungsten B is a solid phase of tungsten still unknown to science. The only difference between it and…

Q: Calculate the volume of a unit cell of Nickel in nm3. The volume of unit cell of Nickel is…

Q: The crystal structure of copper is found to be FCC. If two neighboring copper atoms are at a…

Q: if the atomic radius of Silver (Ag) is 0.144 nm, calculate the volume of its unit cell in cubic…

A: Given Atomic radius of Silver ( r ) = 0.144 nm Volume = ?

Q: At room temperature, the edge length of the cubic unit cell in elemental silicon is 5.431 Å, and the…

A: The crystal lattice is a definite ordered structure. A lattice is an arrangement of particles in a…

Q: Calculate the density of gold, which has a face-centered cubic unit cell with an edge length of…

A: Derivation of expression for the density of a face-centered cubic unit cell: In general, density is…

Q: An element crystallizes in a face-centered cubic lattice and has a density of 1.27 g/cm3. The edge…

Q: (3) The unit cell length of NaCl is 5.63 Å. Determine the density of NaCl.

A: We have to calculate the density of the NaCl unit cell.Given:length of unit cell = 5.63 Å

Q: A certain metal M crystallizes in a lattice described by a face-centered cubic (fcc) unit cell.…

A: For a face-centered cubic unit cell, the atoms are aligned along the face diagonal of the unit cell.…

Q: Pure gold crystallizes in a face-centered cubic unit cell with an edge length of 4.08 Å. The alloy…

A: The question concerns the determination of the empirical formula for 18-karat gold, an alloy…

Q: hypothetical metal with an atomic radius of 0.171 nm has an orthorhombic unit cell for which the a,…

A: Atomic Radius of metal = 0.171 nm

Q: Copper (Cu) has an atomic radius of 135 pm and its unit cell is fcc. What is its density in g/cm³?…

Q: 6. A compound consists of A-atoms and B-atoms, and its solid crystal forms a cubic unit cell…

A: Given that, a compound consits two types of atoms A and B respectively. The compound forms a solid…

Q: The spacing of adjacent atoms in a NaCl crystal is 0.282 nm, and the masses of the atoms are 3.82 ×…

A: Spacing of adjacent atoms,a = 0.282 nm = 2.82 x 10-10 m

Q: 3. In a different universe, a certain very heavy element, "Q", forms a simple cubic solid having a…

A: We will use density expression to calculate atomic mass of Q.

Q: adwa Some hypothetical metal has a simple cubic crystal structure. If its atomic weight is 61.25…

A: r = 0.174nm For simple cubic crystal , a= 2r Therefore a = 2×0.174 = 0.348nm…

Q: Q2// To calculate the surface density of atoms on a particular plane in a crystal. Consider the…

Concept explainers

Crystal Lattices and Unit Cell

Consider a crystal. The regular and repeating pattern of constituent particles is the most distinguishing feature of crystalline solids. A crystal lattice is formed when these particles are replaced with representative points. The three-dimensional arrangement of constituent particles is known as a crystal lattice. Unit cell is that the smallest portion of a space lattice which when repeated in several directions, generate the whole lattice. Unit cell is a building block of a lattice. It is the smallest unit of cell.

Question

Part B
Gold has a face-centered cubic arrangement with a unit cell edge length of 4.08 A . How many moles of gold fit in a gold
nanoparticle sheet with a length of 60.1 nm, a width of 20.7 nm , and a thickness of 7.66 nm ?
Express your answer with the appropriate units.
> View Available Hint(s)
µA
Value
Units
Submit
< Return to Assignment
Provide Feedback
Pearson
son Education Inc. All rights reserved. | Terms of Use | Privacy Policy | Permissions | Contact Us |
Show All
utlin..pdf
MacBook Air
DII
DD
F12
F11
F10
F8
F7
(
)
&
7
8
9
}
P
Y
11
+ ||

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

This is a popular solution!

SEE SOLUTION Check out a sample Q&A here

Step 1

Step 2

Step 3

Step 4

Step 5

Trending now

This is a popular solution!

Step by step

Solved in 5 steps with 5 images

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.

Similar questions

Using additive rule calculate the total ionic polarizability and ionic polarizability per unit volume for Sra. Ce.TiO; with x = 0.0 and 0.1. The polarizability (a Å³) of Sr", Ce", Ti“ and O² are listed below. For x = 0.0 and 0.1 the unit cell volume is 59.6 Å³ and 59.0 Å³ respectively. LI Be Ne 1.20 0.19 0.05 2.01 1.82 No Mg Al P 1.80 1.32 0.79 0.87 1.22 Ge Ca Sc TI IV 2.93 2.92 1.45 2.64 2.29 1.65 1.23 Cr Mn Fe II. 1 2.23 i NI Cu 12.04 2.11 K V Co Zn Se As 1.50 1.63 Go Br 3.83 3.16 2.81 1.72 Sr 5.29 4.24 3.81 3.25 3.97 Rb Zr Nb Mo Tc Ag Cd In Sn Te IV 4.27 5.23 BI 6.12 Sb 3.40 2.62 2.83 Cs Ba La Hf Ta Re Au Hg TI Pb 7.43 6.40 6.07 4.73 7.28 6.58 Ce Nd Sm Yb Pr 16.15 IV3.94 Pm Dy 4.74 4.83 4.37 4.25 4.07 3.97 3.81 3.02 3.50 3.64 Eu Gd Tb Но Er Tm Lu 5.32 5.01 4.53 Th Pa 4.92 IV 4.45 FIG. 1. Table of ion dielectric polarizabilities given in Å'. o Jn
2. What is the overall charge on the 2:1 layer in a smectite with a 2:l layer composition of Alı sMgo 2Si3 sAlo 2010(OH)2? What is the overall charge on the 1:1 layer of kaolinite with a composition of Al,SizOs(OH),? What implications does this have for the cation exchange capacity of each (< 3 sentences)?
55
- & Sketch New · C $ 7 ♡ www 1500 kg/m³ O 3000 kg/m³ 5000 kg/m³ 7000 kg/m³ 9000 kg/m³ 44 < HD E Material X has an atomic radius R = 0.125 nm, an atomic weight of A = 51 g/mol, and a body centered cubic (BCC) crystal structure. Calculate the mass density of this material. Hint: Do your calculations in SI units, as this will help avoid numerical errors from unit conversions. Choose the answer closest to your calculated value.
c. The table below shows characteristics of two dopants added in Czochralski growth processes of crystalline silicon. In both, a mass M of the dopant was added to 1 kg of silicon. Growth 01 Silicon mass Dopant mass Dopant atomic weight (molar mass) Distribution coefficient (ka) 1 kg M 74.9 g/mol 0.3 1.0 x 10¹5 cm- Growth 02 1 kg M 31 g/mol 0.36 Doping concentration 22 As shown in the table above, we got doping of 1.0 x 10¹5 cm3 for the first process (Growth 01), what is the doping concentration that we will get in the second process (Growth 02) ? A) 0.5 x 10¹5 cm-3 B) 2.0 x 10¹5 cm-³ Answer C) 2.9 x 10¹5 cm-3D) 3.4 x 10¹4 cm-3
A common feature in high-temperature ceramic superconductors is a Cu-O sheet that serves as a superconducting plane. Calculate the coulombic force of attraction between a Cu and an O within one of these sheets. Express your answer to three significant figures. Va AE t vec F- Submit Request Answer
3
fast nd fully solved pls
typing
1) For a crystalline substance with a hexagonal unit cell, the distance interplanar d is given by the expression. Consider graphite, for which a = 0.247 nm and c = 0.679 nm. On a standardized diffractogram with Cu Kα radiation ((λ = 1.5418 Å)), where angle 2θ will be observed the Bragg 002 peak of graphite?
(b) Answer both: i. Define Refractory material and give its one application. ii. Define porosity of refractory and its effect on strength.
9) A Cu monocrystal (FCC) of 10 cm length is pulled in tension. The stress axis is [¯123].a) Which is the stress system with the highest resolved shear stress?(b) If the extension of the crystal continues until a second slip systembecomes operational, what will this system be?(c) What rotation will be required to activate the second system?(d) How much longitudinal strain is required to activate the second system?