**Question:**What is the orbital period of a bit of matter in an accretion disk that is located \(3 \times 10^5\) km from a \(29 \, M_{\odot}\) black hole? *(Hint: Use the circular orbit velocity formula, \( V_c = \sqrt{\frac{GM}{r}} \).***Answer:** [ ] sIn this problem, you are tasked with finding the orbital period of matter in an accretion disk around a black hole. The mass of the black hole is \(29 \, M_{\odot}\), where \(M_{\odot}\) represents the solar mass, and the distance from the black hole is \(3 \times 10^5\) km. The hint provided suggests using the formula for circular orbit velocity:\[ V_c = \sqrt{\frac{GM}{r}} \]In this formula:- \(G\) is the gravitational constant.- \(M\) is the mass of the black hole.- \(r\) is the distance from the black hole.You will need to integrate this formula into the calculation for the orbital period to find the answer.

Time period was found to be 526 seconds So answer to fill in blank is 526. Detailed solution is…

Answered: GM What is the orbital period of a bit…

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GM What is the orbital period of a bit of matter in an accretion disk that is located 3 x 105 km from a 29 M. black hole? (Hint: Use the circular orbit velocity formula, V. = V