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Glycerin SG = 1.26 Water SG = 1.0 Oil SG = 0.88 60 cm 10 cm в 15 cm 20 cm Mercury SG = 13.5

Glycerin SG = 1.26 Water SG = 1.0 Oil SG = 0.88 60 cm 10 cm в 15 cm 20 cm Mercury SG = 13.5

Introduction to Chemical Engineering Thermodynamics
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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A) calculate the pressure difference AP=PB-PA of the below manometer. Glycerin SG = 1.26 Water SG = 1.0 Oil SG = 0,88 60 cm 10 cm 15 cm 20 cm Mercury SG = 13.5 b) An aqueous solution has a specific gravity of 2.5 and contains 12mol% salt (MM=60) and 88mole % water. The flow rate of this solution is 250g/s. Calculate the followings (а) Average molecular weight of the mixture (b) Molar flow rate of the solution (lbmol/hr) (c) Mass fractions of the salt and water (d) Mass flow rate of salt (kg/min) (e) Concentration of salt in solution (lbm/ft3) (f) Morality of salt in solution
Transcribed Image Text:A) calculate the pressure difference AP=PB-PA of the below manometer. Glycerin SG = 1.26 Water SG = 1.0 Oil SG = 0,88 60 cm 10 cm 15 cm 20 cm Mercury SG = 13.5 b) An aqueous solution has a specific gravity of 2.5 and contains 12mol% salt (MM=60) and 88mole % water. The flow rate of this solution is 250g/s. Calculate the followings (а) Average molecular weight of the mixture (b) Molar flow rate of the solution (lbmol/hr) (c) Mass fractions of the salt and water (d) Mass flow rate of salt (kg/min) (e) Concentration of salt in solution (lbm/ft3) (f) Morality of salt in solution
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