Glucose 1-Phosphate → Glucose 6-Phosphate Glucose 1-Phosphate → Glucose 6-Phosphate • (AG = -1.7 kcal/mole, K. = 19) • Is the reaction exergonic or endergonic? Exergonic - gives off 1.7 kcal/mole. Reaction to Reaction to equilibrium equilibrium 100% Glucose 6-phosphate 100% Glucose 1-phosphate 95% Glucose 6-phosphate If reaction begins with 20 moles Glucose 1-PO4, how much Glucose 1-PO, and Glucose 6-PO, is present at Chemical Equilibrium? • K. = [Products]/[Reactants] • K=19, so will be 19 moles of Product (G 6-P) for every 1 mole of Reactant (G 1-P) Reaction to equilibrium Reaction to equilibrium 100% Glucose 100% Glucose 1-phosphate 6-phosphate 95% Glucose 6-phosphate 5% Glucose
Glucose 1-Phosphate → Glucose 6-Phosphate Glucose 1-Phosphate → Glucose 6-Phosphate • (AG = -1.7 kcal/mole, K. = 19) • Is the reaction exergonic or endergonic? Exergonic - gives off 1.7 kcal/mole. Reaction to Reaction to equilibrium equilibrium 100% Glucose 6-phosphate 100% Glucose 1-phosphate 95% Glucose 6-phosphate If reaction begins with 20 moles Glucose 1-PO4, how much Glucose 1-PO, and Glucose 6-PO, is present at Chemical Equilibrium? • K. = [Products]/[Reactants] • K=19, so will be 19 moles of Product (G 6-P) for every 1 mole of Reactant (G 1-P) Reaction to equilibrium Reaction to equilibrium 100% Glucose 100% Glucose 1-phosphate 6-phosphate 95% Glucose 6-phosphate 5% Glucose
Biochemistry
9th Edition
ISBN:9781319114671
Author:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.
Publisher:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.
Chapter1: Biochemistry: An Evolving Science
Section: Chapter Questions
Problem 1P
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