[Glc-1-P]eq + [Glc-6-P]eq = 1 M Kéq = [Glc-6-P]éq [Glc-1-P]éq = 18,78 from equation 1 and 2 can you exlain how we get the equation below : (18,78 + 1) [Glc-1-P]éq = 1 M [Glc-1-Pleq [Glc-6-P] = 1 M -0,05056 M = - 1 2 1 M 19,78 0,94944 M = 0,05056 M

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