Giving a test to a group of students, the grades and gender are summarized below. Round your answers to 4 decimal places. Grades and Gender A В Total Male 14 4 12 30 Female 7 9. 3 19 Total 21 13 15 49 If one student is chosen at random, a. Find the probability that the student got a C: 0.3061 b. Find the probability that the student was female AND got a "C": 0.0612 c. Find the probability that the student was male OR got a "C": d. If one student is chosen at random, find the probability that the student was female GIVEN they got a 'C':

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### Probabilities of Student Grades by Gender

#### Data Summary
A test was administered to a group of students, and the results are categorized by grades (A, B, C) and gender (Male, Female). The following table summarizes the data:

| Grades and Gender | A  | B  | C  | Total |
|-------------------|----|----|----|-------|
| Male              | 14 | 4  | 12 | 30    |
| Female            | 7  | 9  | 3  | 19    |
| **Total**         | 21 | 13 | 15 | 49    |

#### Probability Calculations

The task is to find the probabilities for various scenarios when a student is chosen at random. The answers must be rounded to four decimal places.

**a. Probability that a student got a C**

To find this probability, divide the total number of students who got a C by the total number of students:

\[
P(C) = \frac{15}{49} \approx 0.3061
\]

**b. Probability that the student was female AND got a C**

For this probability, consider the number of females who got a C divided by the total number of students:

\[
P(\text{Female and C}) = \frac{3}{49} \approx 0.0612
\]

**c. Probability that the student was male OR got a C**

This probability involves students who are either male, got a C, or both. Use the formula for the probability of A OR B:

\[
P(\text{Male or C}) = P(\text{Male}) + P(C) - P(\text{Male and C})
\]

Calculate each:

- \( P(\text{Male}) = \frac{30}{49} \)
- \( P(C) = \frac{15}{49} \)
- \( P(\text{Male and C}) = \frac{12}{49} \)

Plug these into the formula:

\[
P(\text{Male or C}) = \frac{30}{49} + \frac{15}{49} - \frac{12}{49} = \frac{33}{49} \approx 0.6735
\]

**d. Probability that the student was female GIVEN they got a C**

This is a conditional probability question. Calculate it by
Transcribed Image Text:### Probabilities of Student Grades by Gender #### Data Summary A test was administered to a group of students, and the results are categorized by grades (A, B, C) and gender (Male, Female). The following table summarizes the data: | Grades and Gender | A | B | C | Total | |-------------------|----|----|----|-------| | Male | 14 | 4 | 12 | 30 | | Female | 7 | 9 | 3 | 19 | | **Total** | 21 | 13 | 15 | 49 | #### Probability Calculations The task is to find the probabilities for various scenarios when a student is chosen at random. The answers must be rounded to four decimal places. **a. Probability that a student got a C** To find this probability, divide the total number of students who got a C by the total number of students: \[ P(C) = \frac{15}{49} \approx 0.3061 \] **b. Probability that the student was female AND got a C** For this probability, consider the number of females who got a C divided by the total number of students: \[ P(\text{Female and C}) = \frac{3}{49} \approx 0.0612 \] **c. Probability that the student was male OR got a C** This probability involves students who are either male, got a C, or both. Use the formula for the probability of A OR B: \[ P(\text{Male or C}) = P(\text{Male}) + P(C) - P(\text{Male and C}) \] Calculate each: - \( P(\text{Male}) = \frac{30}{49} \) - \( P(C) = \frac{15}{49} \) - \( P(\text{Male and C}) = \frac{12}{49} \) Plug these into the formula: \[ P(\text{Male or C}) = \frac{30}{49} + \frac{15}{49} - \frac{12}{49} = \frac{33}{49} \approx 0.6735 \] **d. Probability that the student was female GIVEN they got a C** This is a conditional probability question. Calculate it by
The table summarizes results from 984 pedestrian deaths that were caused by automobile accidents.

**Pedestrian Deaths**

| Driver Intoxicated? | Pedestrian Intoxicated? | Yes | No  |
|---------------------|-------------------------|-----|-----|
| Yes                 |                         |  62 |  85 |
| No                  |                         | 225 | 612 |

If one of the pedestrian deaths is randomly selected, find the probability that the pedestrian was not intoxicated. *Please enter a decimal to 4 places.*
Transcribed Image Text:The table summarizes results from 984 pedestrian deaths that were caused by automobile accidents. **Pedestrian Deaths** | Driver Intoxicated? | Pedestrian Intoxicated? | Yes | No | |---------------------|-------------------------|-----|-----| | Yes | | 62 | 85 | | No | | 225 | 612 | If one of the pedestrian deaths is randomly selected, find the probability that the pedestrian was not intoxicated. *Please enter a decimal to 4 places.*
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