Giving a test to a group of students, the grades and gender are summarized below A B C Total Male 14 4 20 38 Female 17 9 19 45 Total 31 13 39 83 Let p represent the population proportion of all male students who received a grade of C on this test. Use a 80% confidence interval to estimate p to four decimal places if possible

Giving a test to a group of students, the grades and gender are summarized below A B C Total Male 14 4 20 38 Female 17 9 19 45 Total 31 13 39 83 Let p represent the population proportion of all male students who received a grade of C on this test. Use a 80% confidence interval to estimate p to four decimal places if possible

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

Lo A life satisfaction measure is normally distributed with u = 66. Nine individuals with only a primary education are randomly selected to take the life satisfaction measure. Construct and interpret a 90% confidence interval based on the samples results in the table below. 56 57 60 63 68 63 47 45 63
Giving a test to a group of students, the grades and gender are summarized below A B Total Male 17 14 37 Female 15 Total 32 27 21 11 64 Let p represent the proportion of all male students who would receive a grade of B on this test. Use a 855 confidence interval to estimatep to three decimal places. ule
Giving a test to a group of students, the grades and gender are summarized below A B C Total Male 29 20 34 83 Female 43 26 25 94 Total 72 46 59 177 Use the table above to get a 90% confidence interval for the percentage of all female students who would receive a grade of A on this test.Enter your answers below using decimals. < P <
The heart rates for a group of 17 students taking a final exam are given below. Assume heart rates are normally distributed. Use a TI-83, TI-83 plus, or TI-84 calculator to find the 95% confidence interval for the true population mean. Round your answers to two decimal places and use increasing order. Beats per minute 92 101 93 89 93 89 92 95 86 93 96 93 96 87 94 97 101
Construct the 99.5% confidence interval for the difference p, - p, when x, = 50, n, = 75, x, = 65, and n, = 151. Round the answers to three decimal places. A 99,5% confidence interval for the difference between the two proportions is
The figure to the right shows the results of a survey in which 1500 college graduates from the year 2016 were asked questions about employment. Employment College students' responses to questions about employment Construct 99% confidence intervals for the population proportion of college students who gave each response. Expect to stay at firet employer for 3 or more years 73% Comploted an apprenticeship or intemship 67% Employed in field of study 61% Foel underemployed 53% Prefer to work for a large company 17% The 99% confidence interval for the proportion of college students that expect to stay at their first émployer for 3 or more years is ( D. (Round to three decimal places as needed.)
A survey asked, "How many tattoos do you currently have on your body?" Of the 1233 males surveyed, 183 responded that they had at least one tattoo. Of the 1042 females surveyed, 139 responded that they had at least one tattoo. Construct a 95% confidence interval to judge whether the proportion of males that have at least one tattoo differs significantly from the proportion of females that have at least one tattoo. Interpret the interval. C Let p₁ represent the proportion of males with tattoos and p2 represent the proportion of females with tattoos. Find the 95% confidence interval for p₁ -P2- The lower bound is The upper bound is (Round to three decimal places as needed.)
Giving a test to a group of students, the grades and gender are summarized below A B C Total Male 9 7 5 21 Female 3 4 15 22 Total 12 11 20 43 Let p represent the population proportion of all male students who received a grade of B on this test. Use a 85% confidence interval to estimate p to four decimal places if possible.
In interval estimation, as the sample size becomes larger, the interval estimate becomes narrower. becomes wider. remains the same, because the mean is not changing. gets closer to 1.96.
Need help of the Find the Confidence Interval section
You are interested in finding a 90% confidence interval for the mean number of visits for physical therapy patients. The data below show the number of visits for 13 randomly selected physical therapy patients. Round answers to 3 decimal places where possible. 15 26 28 28 14 11 18 20 5 19 15 14 19 a. To compute the confidence interval use a Correct distribution. b. With 90% confidence the population mean number of visits per physical therapy patient is between and visits. c. If many groups of 13 randomly selected physical therapy patients are studied, then a different confidence interval would be produced from each group. About percent of these confidence intervals will contain the true population mean number of visits per patient and about percent will not contain the true population mean number of visits per
The figure to the right shows the results of a survey in which 2000 college graduates from the year 2016 were asked questions about employment. Construct 99% confidence intervals for the population proportion of college students who gave each response. Employment College students' responses to questions about employment Expect to stay at first employer for 3 or more years Completed an apprenticeship or internship 70% 66% Employed in field of study 61% Feel underemployed 46% Prefer to work for a large company 15% The 9970 Conuenit initivaliui int proportion un cuiityt diuutid inal txptul iu diay al ineli idi empivyti iui j'ui muit years is (0.01, 0.121). (Round to three decimal places as needed.) The 99% confidence interval for the proportion of college students that have completed an apprenticeship or internship is (J.). (Round to three decimal places as needed.)