#*3EDGiving a test to a group of students, the grades and gender are summarized belowABC TotalMale 12 20386Female 16 18 1549Total 28 38 2187Let p represent the population proportion of all male students who received a grade of C on this test. Use a98% confidence interval to estimate p to four decimal places if possible.

Here, x =21 The sample size n = 81. The absolute value of Zα/2 is 2.3263 using the Excel formula…

Answered: Giving a test to a group of students,…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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If n=550 and X = 440, construct a 90% confidence interval. Give your answers to three decimals
A random survey of 200 pregnant women in New York City conducted by Epstein andRogers indicated that 150 of them preferred a female obstetrician to a male obstetrician.a. Find a point estimate for p, the proportion of all pregnant women in New York Citywho prefer a female obstetrician.__________ b. Find a 99% confidence interval for the proportion p of all pregnant women living inNew York City who prefer a female obstetrician.
Giving a test to a group of students, the grades and gender are summarized below A B C Total Male 24 48 34 106 Female 40 26 22 88 Total 64 74 56 194 Use the table above to get a 95% confidence interval for the percentage of all female students who would receive a grade of B on this test.Enter your answers below using decimals. < P <
Use the given confidence interval to find the margin of error and the sample proportion. (0.729,0.755) E=enter your response here (Type an integer or a decimal.)
Lo A life satisfaction measure is normally distributed with u = 66. Nine individuals with only a primary education are randomly selected to take the life satisfaction measure. Construct and interpret a 90% confidence interval based on the samples results in the table below. 56 57 60 63 68 63 47 45 63
Giving a test to a group of students, the grades and gender are summarized below A B C Total Male 29 20 34 83 Female 43 26 25 94 Total 72 46 59 177 Use the table above to get a 90% confidence interval for the percentage of all female students who would receive a grade of A on this test.Enter your answers below using decimals. < P <
Giving a test to a group of students, the grades and gender are summarized below A B C Total Male 9 7 5 21 Female 3 4 15 22 Total 12 11 20 43 Let p represent the population proportion of all male students who received a grade of B on this test. Use a 85% confidence interval to estimate p to four decimal places if possible.
Need help of the Find the Confidence Interval section
The accompanying table shows data for the weights of backpacks for men and women. Assume that the data are from random samples and the distributions are Normal. Complete parts (a) and (b) below. E Click the icon to view the data table. a. Find a 95% confidence interval for the difference between means HFemale - HMale state whether it captures 0, and explain what that shows about the mean. The 95% confidence interval is ( D (Round to two decimal places as needed. Use ascending order.) Backpack weights Female Male 10 10 12 8 9. 7 5 10 7 20 3 11 8 14 13 11 14 6 7 22 11 12 15 10 17 22 10 7 25 11 7 15 11 11 4 16 13 20 21 15 10 9. 16 10 15 13 10 10 17 12 11 38 6. 6. 7 19 12 13 20 8 14 15 18 19 10 16 16 13 18 12 14 13 13 15 14 14 7 7 14 13 27 11
You are interested in finding a 90% confidence interval for the mean number of visits for physical therapy patients. The data below show the number of visits for 13 randomly selected physical therapy patients. Round answers to 3 decimal places where possible. 15 26 28 28 14 11 18 20 5 19 15 14 19 a. To compute the confidence interval use a Correct distribution. b. With 90% confidence the population mean number of visits per physical therapy patient is between and visits. c. If many groups of 13 randomly selected physical therapy patients are studied, then a different confidence interval would be produced from each group. About percent of these confidence intervals will contain the true population mean number of visits per patient and about percent will not contain the true population mean number of visits per
Construct a confidence interval for p, - p2 at the given level of confidence. X1 = 35, n, = 254, x2 = 31, n2 = 300, 90% confidence %3D ... The researchers are % confident the difference between the two population proportions, p, - P2, is between and (Use ascending order. Type an integer or decimal rounded to three decimal places as needed.)

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