Giventhefollowingsetofreactionsandtheirenthalpies,drawtheBorn-Habercyclefortheformationof LiCl(s)anddeterminethelatticeenergyforLiCl.Reactions:H (in kJ)(1)Li(s)Li(g);Hs= 161;(2) Li(g)Li+(g)+e–;IE= 520;(3) ½Cl2(g)Cl(g);½BE =121.5;(4)Cl(g)+ e–Cl–(g);EA= –349;(5)Li+(g)+ Cl–(g)LiCl(s);UL= ?(UL= latticeenergy)(6) Li(s)+ ½ Cl2(g)LiCl(s);Hof=–408.6._______________________________________________________________________________

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Giventhefollowingsetofreactionsandtheirenthalpies,drawtheBorn-Habercyclefortheformationof LiCl(s)anddeterminethelatticeenergyforLiCl.Reactions:H (in kJ)(1)Li(s)Li(g);Hs= 161;(2) Li(g)Li+(g)+e–;IE= 520;(3) ½Cl2(g)Cl(g);½BE =121.5;(4)Cl(g)+ e–Cl–(g);EA= –349;(5)Li+(g)+ Cl–(g)LiCl(s);UL= ?(UL= latticeenergy)(6) Li(s)+ ½ Cl2(g)LiCl(s);Hof=–408.6._______________________________________________________________________________

Expert Solution
Step 1

Given information:

Sublimation enthalpy for Li = 161 kJ

Ionization enthalpy for Li = 520 kJ

Dissociation energy = 121.5 kJ

Electron gain enthalpy = -349 kJ

Enthalpy of formation of LiCl = 408.6 kJ

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