Given:(NH4)2SO4 + Ba(NO3)2 -->___NH4NO3 +___BaSO4 54.6g of ammonium sulfate reacts with 67.8g of barium nitrate. A) What is the limiting reactant? B) What mass of barium sulfate will be produced? Answer A): Limiting Reactant, Answer B): number unit of formula Answer A): *For chemical formulas: enter subscripts as normal number, and no spaces. << Previous 80 F3 JAN 24 Q F4 9 , Answer B): F5 tv c F6 K F7 A DII F8 A of N F9

Chemistry
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Given:(NH4)2SO4 +___Ba(NO3)2 -- ____NH4NO3 +___BaSO4
54.6g of ammonium sulfate reacts with 67.8g of barium nitrate.
A) What is the limiting reactant?
B) What mass of barium sulfate will be produced?
Answer A): Limiting Reactant, Answer B): number unit of formula
#3
Answer A):
*For chemical formulas: enter subscripts as normal number, and no spaces.
◄ Previous
80
F3
JAN
24
$
4
Q
F4
%
5
Answer B):
9
F5
6
1
tv
c
F6
&
7
F7
* 00
8
DII
F8
- O
9
of
F9
Transcribed Image Text:Given:(NH4)2SO4 +___Ba(NO3)2 -- ____NH4NO3 +___BaSO4 54.6g of ammonium sulfate reacts with 67.8g of barium nitrate. A) What is the limiting reactant? B) What mass of barium sulfate will be produced? Answer A): Limiting Reactant, Answer B): number unit of formula #3 Answer A): *For chemical formulas: enter subscripts as normal number, and no spaces. ◄ Previous 80 F3 JAN 24 $ 4 Q F4 % 5 Answer B): 9 F5 6 1 tv c F6 & 7 F7 * 00 8 DII F8 - O 9 of F9
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