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Given: ZA ZB, mZA= (x+2)+39, and m/B=5(x-3) Prove: x = 12 Statement: 1. ZA ZB 2.mZA=mZB 3.m

Given: ZA ZB, mZA= (x+2)+39, and m/B=5(x-3) Prove: x = 12 Statement: 1. ZA ZB 2.mZA=mZB 3.m

Algebra and Trigonometry (6th Edition)
Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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Given: ZA ZB, mZA = (x + 2) + 39, and m/B=5(x-3) Prove: x = 12 Statement: 1. ZA ZB 2.m<A=m<B 3.m<A = (x+2)+39 4.m/B=5(x-3) 8.x = 10x - 108 9.-9x=-108 Reason: 10.x = 12 1. Given 2. Congruency 3. Given 5. (x+2)+39= 5(x-3) 5.[?] 6. (x+2)+39=5x-15 7.x = 2 = 5x-54 4. Given 6. Distributive Property 7. Subtraction Property of Equality 8. 9. Subtraction Property of Equality 10. Division Property of Equality
Transcribed Image Text:Given: ZA ZB, mZA = (x + 2) + 39, and m/B=5(x-3) Prove: x = 12 Statement: 1. ZA ZB 2.m<A=m<B 3.m<A = (x+2)+39 4.m/B=5(x-3) 8.x = 10x - 108 9.-9x=-108 Reason: 10.x = 12 1. Given 2. Congruency 3. Given 5. (x+2)+39= 5(x-3) 5.[?] 6. (x+2)+39=5x-15 7.x = 2 = 5x-54 4. Given 6. Distributive Property 7. Subtraction Property of Equality 8. 9. Subtraction Property of Equality 10. Division Property of Equality
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