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Given y(x) =Inx+4e*. Find the value of m if y(x) is a solution for y" – y' = m 1 1 -+ +8e² (x²

Given y(x) =Inx+4e*. Find the value of m if y(x) is a solution for y" – y' = m 1 1 -+ +8e² (x²

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Given = 1 Find the value of m if y(x) is a solution for y" – y' = m| +8e*. + Oa. 1 y =+8e", 3x 1 – 16e*. 3x? Substitute into the differential equation: %3D y-y-- -22. Hence m =-3. 1 + |– 22e²* . Hence m=-3. Ob. 1 ·+8e²* 3.x 1 y" = +16e²*. Substitute into the differential equation: 3x2 y" – y' = - +8e2*. Hence m=- 3 1 y' = +2e²* 3x 1 y": 3x² ·+e² Substitute into the differential equation: %3D 1( 1 y -y =- 3 x 1 ex. Hence 1m = 3 od. y =+8e*, 3x , y-+16ent. Substitute into the differential equation: 3.x 1( 1 1 1 +8e?*. Hence m=- 3
Transcribed Image Text:Given = 1 Find the value of m if y(x) is a solution for y" – y' = m| +8e*. + Oa. 1 y =+8e", 3x 1 – 16e*. 3x? Substitute into the differential equation: %3D y-y-- -22. Hence m =-3. 1 + |– 22e²* . Hence m=-3. Ob. 1 ·+8e²* 3.x 1 y" = +16e²*. Substitute into the differential equation: 3x2 y" – y' = - +8e2*. Hence m=- 3 1 y' = +2e²* 3x 1 y": 3x² ·+e² Substitute into the differential equation: %3D 1( 1 y -y =- 3 x 1 ex. Hence 1m = 3 od. y =+8e*, 3x , y-+16ent. Substitute into the differential equation: 3.x 1( 1 1 1 +8e?*. Hence m=- 3
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