Given vectors a=(0,-3) and b=(2,0) Find the y-component of the resultant vector: T = 2a + 36

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Chapter1: Units, Trigonometry. And Vectors
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**Vectors and Resultants: Calculating the Y-Component**

**Given:**
- \(\vec{a} = (0, -3)\)
- \(\vec{b} = (2, 0)\)

**Problem:**
Find the y-component of the resultant vector:
\[\vec{r} = 2 \vec{a} + 3 \vec{b}\]

**Solution:**

We start with the given vectors:
\(\vec{a} = (0, -3)\)
\(\vec{b} = (2, 0)\)

We need to calculate the resultant vector:
\[\vec{r} = 2 \vec{a} + 3 \vec{b}\]

First, we scale each vector:
\[2 \vec{a} = 2(0, -3) = (0, -6)\]
\[3 \vec{b} = 3(2, 0) = (6, 0)\]

Next, we add the scaled vectors to get the resultant vector \(\vec{r}\):
\[\vec{r} = (0, -6) + (6, 0) = (6, -6)\]

Finally, the y-component of the resultant vector \(\vec{r} = (6, -6)\) is:
\[y \text{-component} = -6\]

Thus, the y-component of the resultant vector is \(-6\).
Transcribed Image Text:**Vectors and Resultants: Calculating the Y-Component** **Given:** - \(\vec{a} = (0, -3)\) - \(\vec{b} = (2, 0)\) **Problem:** Find the y-component of the resultant vector: \[\vec{r} = 2 \vec{a} + 3 \vec{b}\] **Solution:** We start with the given vectors: \(\vec{a} = (0, -3)\) \(\vec{b} = (2, 0)\) We need to calculate the resultant vector: \[\vec{r} = 2 \vec{a} + 3 \vec{b}\] First, we scale each vector: \[2 \vec{a} = 2(0, -3) = (0, -6)\] \[3 \vec{b} = 3(2, 0) = (6, 0)\] Next, we add the scaled vectors to get the resultant vector \(\vec{r}\): \[\vec{r} = (0, -6) + (6, 0) = (6, -6)\] Finally, the y-component of the resultant vector \(\vec{r} = (6, -6)\) is: \[y \text{-component} = -6\] Thus, the y-component of the resultant vector is \(-6\).
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