Given vector v = (-2,5) and vector u = (6,8), what are the endpoints of vector v + u? v+u = (8,13) V+U=(4,13) V+u = (13,4) V+U=(4,3)

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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**Vector Addition Question**

**Problem Statement:**
Given vector \( \mathbf{v} = \langle -2, 5 \rangle \) and vector \( \mathbf{u} = \langle 6, 8 \rangle \), what are the endpoints of vector \( \mathbf{v} + \mathbf{u} \)?

**Answer Choices:**
- \( \mathbf{v} + \mathbf{u} = \langle 8, 13 \rangle \)
- \( \mathbf{v} + \mathbf{u} = \langle 4, 13 \rangle \)
- \( \mathbf{v} + \mathbf{u} = \langle 13, 4 \rangle \)
- \( \mathbf{v} + \mathbf{u} = \langle 4, 3 \rangle \)
Transcribed Image Text:**Vector Addition Question** **Problem Statement:** Given vector \( \mathbf{v} = \langle -2, 5 \rangle \) and vector \( \mathbf{u} = \langle 6, 8 \rangle \), what are the endpoints of vector \( \mathbf{v} + \mathbf{u} \)? **Answer Choices:** - \( \mathbf{v} + \mathbf{u} = \langle 8, 13 \rangle \) - \( \mathbf{v} + \mathbf{u} = \langle 4, 13 \rangle \) - \( \mathbf{v} + \mathbf{u} = \langle 13, 4 \rangle \) - \( \mathbf{v} + \mathbf{u} = \langle 4, 3 \rangle \)
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