Given the vector-valued function R(t) = -6cos(1-2t) i+8t j+6 sin(1 2t) k. Find: (a) the length of arc of the curve from t = In 2 to t= In 4; %3D (b) the unit tangent vector at t (c) the unit normal vector at t %3D

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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4. Given the vector-valued function R(t)
2t) k. Find:
-6 cos(1-2t) i+8t j+6 sin(1-
%3D
(a) the length of are of the curve fromt In 2 tot = In 43B
%3D
%3D
(b) the unit tangent vector at t=
(c) the unit normal vector at t =
%3D
Transcribed Image Text:4. Given the vector-valued function R(t) 2t) k. Find: -6 cos(1-2t) i+8t j+6 sin(1- %3D (a) the length of are of the curve fromt In 2 tot = In 43B %3D %3D (b) the unit tangent vector at t= (c) the unit normal vector at t = %3D
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