Given the vector function (1) = (e+→¹², 2√³+1, 4 arctan(1-1)), find the speed and the equation of the tangent line to this curve at t = 2, then graph the tangent line. Speed= i(t) =
Given the vector function (1) = (e+→¹², 2√³+1, 4 arctan(1-1)), find the speed and the equation of the tangent line to this curve at t = 2, then graph the tangent line. Speed= i(t) =
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Transcribed Image Text:Given the vector function r(t) = (e+²³, 2√1³ +1, 4 arctan(1 − 1) find the speed and the
equation of the tangent line to this curve at t = 2, then graph the tangent line.
Speed =
i(t) =
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