Answered: Given the UV Spectrum pictured for…

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Question

Given the UV Spectrum pictured for Sulforhodamine 101. What is the fraction of light absorbed at the wavelength of maximum absorption?

0.5
290
300
305
310
315
A(nm)
% Transmission
% Absorbtion
Absorbance
2.

Expert Solution

Step 1-Introduction

The quantity of the light incident (I₀) on the cell with the length L and the intensity of the light coming out of the cell (I) is related to the absorbance of the solution (A) as follows: $A = \log_{10} (\frac{I_{0}}{I}) . . . (1)$ . The percent of the transmitted light (%T) is related to the absorbance A as follows: $A = 2.000 - \log (% T) . . . (2)$ . Besides, the absorbance of the solution is related to the concentration (C), L, and molar extinction coefficient ( $ε$ ) as follows: $A = ε C l$ .

Step 2-Determination of the absorbance (A)

From the graph, the percent transmission is observed as 0.3%. Substitute the value in equation 1 to evaluate the absorbance A.

$\begin{array}{rcl} % T & = & 0.3 \\ A & = & 2 - \log (% T) \\ = & 2 - \log (0.3) \\ = & 2 - (- 0.523) \\ A & = & 2.523 \end{array}$

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