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Given the Ultimate analysis of Alabama coal: Sulfur = 2.12% Hydrogen = 4.28% Ash = 6.40% Carbon = 77.76% Nitrogen = 2.92% Oxygen = 6.52% Moisture = 3.62% Using Ash and Moisture-free analysis, calculate the Actual A/F ratio at 15% excess air.

Given the Ultimate analysis of Alabama coal: Sulfur = 2.12% Hydrogen = 4.28% Ash = 6.40% Carbon = 77.76% Nitrogen = 2.92% Oxygen = 6.52% Moisture = 3.62% Using Ash and Moisture-free analysis, calculate the Actual A/F ratio at 15% excess air.

Introduction to Chemical Engineering Thermodynamics
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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Given the Ultimate analysis of Alabama coal: Sulfur = 2.12% Hydrogen Ash = 6.40% Carbon = 77.76% Nitrogen = 2.92% Oxygen = 6.52% Moisture = 3.62% Using Ash and Moisture-free analysis, calculate the Actual A/F ratio at 15% excess air. = 4.28%
Transcribed Image Text:Given the Ultimate analysis of Alabama coal: Sulfur = 2.12% Hydrogen Ash = 6.40% Carbon = 77.76% Nitrogen = 2.92% Oxygen = 6.52% Moisture = 3.62% Using Ash and Moisture-free analysis, calculate the Actual A/F ratio at 15% excess air. = 4.28%
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