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Given the Ultimate analysis of Alabama coal: Sulfur = 1.12% Carbon = 78.76% = 1.42% Oxygen = 6.02% = 3.37 % Using the Ash and Moisture Free analysis, calculate the Lower Heating Value of Coal in BTU/lb. Hydrogen Nitrogen Moisture = 5.28% Ash = 7.40%

Given the Ultimate analysis of Alabama coal: Sulfur = 1.12% Carbon = 78.76% = 1.42% Oxygen = 6.02% = 3.37 % Using the Ash and Moisture Free analysis, calculate the Lower Heating Value of Coal in BTU/lb. Hydrogen Nitrogen Moisture = 5.28% Ash = 7.40%

Introduction to Chemical Engineering Thermodynamics
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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Given the Ultimate analysis of Alabama coal: Sulfur = 1.12% = 5.28% Carbon = 78.76% = 1.42% Oxygen = 6.02% = 3.37 % Using the Ash and Moisture Free analysis, calculate the Lower Heating Value of Coal in BTU/lb. Hydrogen Nitrogen Moisture Ash = 7.40%
Transcribed Image Text:Given the Ultimate analysis of Alabama coal: Sulfur = 1.12% = 5.28% Carbon = 78.76% = 1.42% Oxygen = 6.02% = 3.37 % Using the Ash and Moisture Free analysis, calculate the Lower Heating Value of Coal in BTU/lb. Hydrogen Nitrogen Moisture Ash = 7.40%
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