Given the third-order linear homogeneous differential equation: y (3) - y=0 Select all correct answers Hide answer choices A A B If y (0)=0. y' (0) =1. y' (0) = -1 3 (-1/2) sin( et, e then y=(- 2 is a solution of the associated initial value problem. Three linearly independent solutions of the given differential equation are: el X x + x) -*/2, xe¯*/2

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
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### Differential Equations Overview

The image contains a discussion on differential equations, specifically focusing on linearly independent solutions and initial value problems.

**Section C: Linearly Independent Solutions**
Three linearly independent solutions of a given differential equation are presented:
1. \( e^x \)
2. \( e^{x/2} \sin\left(\frac{\sqrt{3}}{2} x\right) \)
3. \( e^{x/2} \cos\left(\frac{\sqrt{3}}{2} x\right) \)

These forms represent a combination of exponential and trigonometric functions, often appearing in solutions to second-order linear differential equations with complex roots.

**Section D: Solution Verification**
It specifies that:
- \( y \equiv 0 \) is a solution of the differential equation \( y^{(3)} - y = 0 \).

This implies that the zero function satisfies the differential equation, acting as a trivial solution.

**Section E: Another Set of Linearly Independent Solutions**
Three alternative linearly independent solutions are provided for another differential equation:
1. \( e^x \)
2. \( e^{-x/2} \sin\left(\frac{\sqrt{3}}{2} x\right) \)
3. \( e^{-x/2} \cos\left(\frac{\sqrt{3}}{2} x\right) \)

These solutions, similarly to Section C, involve exponential decay and oscillatory behavior, suggesting complex conjugate roots.

**Section F: Initial Value Problem**
Given initial conditions:
- \( y(0) = 0 \)
- \( y'(0) = 1 \)
- \( y''(0) = -1 \)

The solution to the initial value problem is specified as:
\[ y = \left(\frac{2}{\sqrt{3}}\right)e^{(-x/2)}\sin\left(\frac{\sqrt{3}}{2} x\right) \]

This solution combines initial conditions with the linearly independent solutions to form a particular solution that satisfies both the differential equation and the specified initial conditions.

### Summary
The discussed sections showcase different solution techniques for differential equations, emphasizing the importance of finding linearly independent solutions and applying initial conditions to derive particular solutions in a well-defined context.
Transcribed Image Text:### Differential Equations Overview The image contains a discussion on differential equations, specifically focusing on linearly independent solutions and initial value problems. **Section C: Linearly Independent Solutions** Three linearly independent solutions of a given differential equation are presented: 1. \( e^x \) 2. \( e^{x/2} \sin\left(\frac{\sqrt{3}}{2} x\right) \) 3. \( e^{x/2} \cos\left(\frac{\sqrt{3}}{2} x\right) \) These forms represent a combination of exponential and trigonometric functions, often appearing in solutions to second-order linear differential equations with complex roots. **Section D: Solution Verification** It specifies that: - \( y \equiv 0 \) is a solution of the differential equation \( y^{(3)} - y = 0 \). This implies that the zero function satisfies the differential equation, acting as a trivial solution. **Section E: Another Set of Linearly Independent Solutions** Three alternative linearly independent solutions are provided for another differential equation: 1. \( e^x \) 2. \( e^{-x/2} \sin\left(\frac{\sqrt{3}}{2} x\right) \) 3. \( e^{-x/2} \cos\left(\frac{\sqrt{3}}{2} x\right) \) These solutions, similarly to Section C, involve exponential decay and oscillatory behavior, suggesting complex conjugate roots. **Section F: Initial Value Problem** Given initial conditions: - \( y(0) = 0 \) - \( y'(0) = 1 \) - \( y''(0) = -1 \) The solution to the initial value problem is specified as: \[ y = \left(\frac{2}{\sqrt{3}}\right)e^{(-x/2)}\sin\left(\frac{\sqrt{3}}{2} x\right) \] This solution combines initial conditions with the linearly independent solutions to form a particular solution that satisfies both the differential equation and the specified initial conditions. ### Summary The discussed sections showcase different solution techniques for differential equations, emphasizing the importance of finding linearly independent solutions and applying initial conditions to derive particular solutions in a well-defined context.
Given the third-order linear homogeneous differential equation:

\[ y^{(3)} - y = 0 \]

**Select all correct answers**

---

**A**

If \( y(0) = 0, \ y'(0) = 1, \ y''(0) = -1 \),

then \[ y = \left(\frac{-2}{\sqrt{3}}\right) e^{(-x/2)} \sin \left( \frac{\sqrt{3}}{2} x + \pi \right) \]

is a solution of the associated initial value problem.

---

Three linearly independent solutions of the given differential equation are:

**B**

\[ e^x, \ e^{-x/2}, \ x e^{-x/2} \]
Transcribed Image Text:Given the third-order linear homogeneous differential equation: \[ y^{(3)} - y = 0 \] **Select all correct answers** --- **A** If \( y(0) = 0, \ y'(0) = 1, \ y''(0) = -1 \), then \[ y = \left(\frac{-2}{\sqrt{3}}\right) e^{(-x/2)} \sin \left( \frac{\sqrt{3}}{2} x + \pi \right) \] is a solution of the associated initial value problem. --- Three linearly independent solutions of the given differential equation are: **B** \[ e^x, \ e^{-x/2}, \ x e^{-x/2} \]
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