TuPlease don't provide the handwriting solution Given the thermochemical equationsX₂ + 3 Y₂ → 2XY,X₂ +2Z₂ → 2XZ₂AH₁ = -330 kJAH₂ = -190 kJ2Y₂+Z₂2Y₂ZAH, = -220 kJCalculate the change in enthalpy for the reaction.4XY, +7Z₂ →6Y₂Z +4XZ₂AH =kJ

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Given the thermochemical equations X₂ + 3 Y₂ → 2XY, AH₁ = -330 kJ X₂ +2Z₂ → 2XZ₂ - AH₂ = -190 kJ 2Y₂+Z₂2Y₂Z AH, = -220 kJ Calculate the change in enthalpy for the reaction. 4XY, +7Z₂ 6Y₂Z +4XZ₂ ΔΗ = 1 kJ

Given the thermochemical equations X₂ + 3 Y₂ → 2XY, AH₁ = -330 kJ X₂ +2Z₂ → 2XZ₂ - AH₂ = -190 kJ 2Y₂+Z₂2Y₂Z AH, = -220 kJ Calculate the change in enthalpy for the reaction. 4XY, +7Z₂ 6Y₂Z +4XZ₂ ΔΗ = 1 kJ

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

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Please don't provide the handwriting solution

Given the thermochemical equations
X₂ + 3 Y₂ → 2XY,
X₂ +2Z₂ → 2XZ₂
AH₁ = -330 kJ
AH₂ = -190 kJ
2Y₂+Z₂2Y₂Z
AH, = -220 kJ
Calculate the change in enthalpy for the reaction.
4XY, +7Z₂ →6Y₂Z +4XZ₂
AH =
kJ

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