Given the system of linear equations, X + Y 2, X + 2y + Z 3, X + Y + (k²-5)z k, where k is a constant. Find the value(s) of k such that the system a) does not have a solution, b) has many solutions, c) has a unique solution. Z =

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1. Given the system of linear equations,
+ Y
+ 2y
X + Y
where k is a constant. Find the value(s)
a) does not have a solution,
b) has many solutions,
c) has a unique solution.
88
X
Z
Z
+
+ (k² − 5)z
=
=
3,
=
k,
of k such that the system
Transcribed Image Text:1. Given the system of linear equations, + Y + 2y X + Y where k is a constant. Find the value(s) a) does not have a solution, b) has many solutions, c) has a unique solution. 88 X Z Z + + (k² − 5)z = = 3, = k, of k such that the system
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