Given the surface z = f (x,y) = x³ + 2x² + 4xy+y², (a) Enter the partial derivative f₂ (1,2), 囡囡 (b) Enter the partial derivative fy (1,2), (c) Enter the coordinates of the point on the surface where x = 1 and y = 2, in the format (x,y,z). (d) Hence enter the equation of the plane that is tangent to z=f(x, y) at that point. For example, if your equation of the plane is 2x+y+z-5=0 enter 2*x+y+z-5.
Given the surface z = f (x,y) = x³ + 2x² + 4xy+y², (a) Enter the partial derivative f₂ (1,2), 囡囡 (b) Enter the partial derivative fy (1,2), (c) Enter the coordinates of the point on the surface where x = 1 and y = 2, in the format (x,y,z). (d) Hence enter the equation of the plane that is tangent to z=f(x, y) at that point. For example, if your equation of the plane is 2x+y+z-5=0 enter 2*x+y+z-5.
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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
Transcribed Image Text:Given the surface z = f(x, y) = x³ + 2x² + 4xy+y²,
(a) Enter the partial derivative fæ (1,2),
(b) Enter the partial derivative fy (1,2),
(c) Enter the coordinates of the point on the surface where x = 1 and y = 2, in the format (x,y,z),
A
(d) Hence enter the equation of the plane that is tangent to z = f (x, y) at that point. For example, if your equation of the plane is 2x+y+z-5= 0,
enter 2*x+y+z-5.
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