Given the singular value decomposition of A: [1/√2 1/√25 001 [1/√2-1/√2] 1/02/10 0 3 0 What is the (2,1) entry of the pseudoinverse of A ? A=UEVT= a) -2/9 b) 2/9 c) 2/45 d) 7/45 e) -2/45 f) -7/45 1/√/2 1/√18 2/3 1/√/2 0 -1/√18 4/√18. -2/3 -1/3

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