Given the same reactant concentrations, the reaction CO(g) + Cl₂(g)→ COC12(8) at 250. °C is 1.50 x 103 times as fast as the same reaction at 150. °C. Calculat the activation energy for this reaction (in kJ/mol). Assume that the frequency factor is constant.

Given the same reactant concentrations, the reaction CO(g) + Cl₂(g)→ COC12(8) at 250. °C is 1.50 x 103 times as fast as the same reaction at 150. °C. Calculat the activation energy for this reaction (in kJ/mol). Assume that the frequency factor is constant.

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

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Question

Given the same reactant concentrations, the reaction
CO(g) + Cl₂(g)
Cl₂(g)→ COCI₂(8)
at 250. °C is 1.50 x 10³ times as fast as the same reaction at 150. °C. Calculate
the activation energy for this reaction (in kJ/mol). Assume that the frequency
factor is constant.
Question 2
The rate constant of a first-order reaction is 4.60 x 10-4s¹ at 350. °C. If the
activation energy is 104 kJ/mol, calculate the temperature (in °C) at which its
rate constant is 8.80 x 10-4 -¹.

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