Given the same 4-link network, OD flow rate of 9, and link travel time functions, use incremental assignment to assign 1/3 of the OD flow at each iteration, report the 4 accumulative link flow and 4 link travel times at the end of each iteration (A total of 12 numbers). th = 9, t2 = 4 + x2, tz = 4 + x3, t4 = 7+x4 Link 1 Link 3 Link 2 Link 4 Figure 7. A 4-Link Network For your convenience, you can copy past the following template for your answers: Iteration 1 x1(1)=, x2(1)=, x3(1)=, x4(1)=. t1(1)=, t2(1)=, t3(1)=, t4(1)=.
Given the same 4-link network, OD flow rate of 9, and link travel time functions, use incremental assignment to assign 1/3 of the OD flow at each iteration, report the 4 accumulative link flow and 4 link travel times at the end of each iteration (A total of 12 numbers). th = 9, t2 = 4 + x2, tz = 4 + x3, t4 = 7+x4 Link 1 Link 3 Link 2 Link 4 Figure 7. A 4-Link Network For your convenience, you can copy past the following template for your answers: Iteration 1 x1(1)=, x2(1)=, x3(1)=, x4(1)=. t1(1)=, t2(1)=, t3(1)=, t4(1)=.
Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
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Transcribed Image Text:Given the same 4-link network, OD flow rate of 9, and link travel time functions, use incremental
assignment to assign 1/3 of the OD flow at each iteration, report the 4 accumulative link flow and 4
link travel times at the end of each iteration (A total of 12 numbers).
ti = 9, t2 = 4 + x2, t3 = 4 + x3, t4 = 7+x4
%3D
%3D
Link 1
Link 3
Link 2
Link 4
Figure 7. A 4-Link Network
For your convenience, you can copy past the following template for your answers:
Iteration 1
x1(1)=, x2(1)=, x3(1)=, x4(1)=.
t1(1)=, t2(1)=, t3(1)=, t4(1)=.
Iteration 2
x1(2)=, x2(2)=, x3(2)=, x4(2)=.
t1(2)=, t2(2)=, t3(2)=, t4(2)=.
Iteration 3
x1(3)=, x2(3)=, x3(3)=, x4(3)=.
t1(3)=, t2(3)=, t3(3)=, t4(3)=.
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