Given the relation schema R(A, B, C) and S(C, D, E), please match each of the following relational algebra expressions to the corresponding SQL (Structured Query Language) statement. (Assume R and S are union compatible) 1. RUS A. SELECT FROM R MINUS SELECT FROM S: B. SELECT FROM S MINUS SELECT C. SELECT D. SELECT E. SELECT F. SELECT 7. RRB S.BS G. SELECT 2. ROS 3. R-S 4.5 R 5. R* S 6. RX S 1 SELECT 8. RRC S.CS H. SELECT INTERSECT 2 3 4 5 6 7 UNION 8 FROM R; FROM R CROSS JOIN S; FROM R NATURAL JOIN S: FROM R JOIN S ON R.C=S.C; FROM R JOIN S ON R.B= S.B; FROM R FROM S: FROM R SELECT FROM S: G H A B D с F E

Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
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Question 5
Given the relation schema R(A, B, C) and S(C, D, E). please match each of the following relational algebra expressions to the corresponding SQL (Structured Query Language) statement.
(Assume R and S are union compatible)
1. RUS
A. SELECT FROM R
MINUS
SELECT * FROM S:
B. SELECT FROM S
2. ROS
SELECT
FROM R:
3. R-S
C. SELECT FROM R CROSS JOIN S;
4.S R
D. SELECT * FROM R NATURAL JOIN S;
5. R* S
E. SELECT
6. RX S
F. SELECT
7. RRB S.BS G. SELECT FROM R
1
2
SELECT FROM S:
8. RRC S.CS H. SELECT FROM R
INTERSECT
4
5
6
MINUS
7
8
UNION
FROM R JOIN S ON R.C=S.C;
FROM R JOIN S ON R.B = S.B;
SELECT FROM S:
G
H
A
B
D
с
F
E
Transcribed Image Text:Question 5 Given the relation schema R(A, B, C) and S(C, D, E). please match each of the following relational algebra expressions to the corresponding SQL (Structured Query Language) statement. (Assume R and S are union compatible) 1. RUS A. SELECT FROM R MINUS SELECT * FROM S: B. SELECT FROM S 2. ROS SELECT FROM R: 3. R-S C. SELECT FROM R CROSS JOIN S; 4.S R D. SELECT * FROM R NATURAL JOIN S; 5. R* S E. SELECT 6. RX S F. SELECT 7. RRB S.BS G. SELECT FROM R 1 2 SELECT FROM S: 8. RRC S.CS H. SELECT FROM R INTERSECT 4 5 6 MINUS 7 8 UNION FROM R JOIN S ON R.C=S.C; FROM R JOIN S ON R.B = S.B; SELECT FROM S: G H A B D с F E
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