Given the reference system, determine the coordinate of the centroid Ycg of the symmetrical plane figure. For therefore, adopt the value of L = 100 + 10·a + 20·(b + 2·c) {mm}. Consider a minimum precision of 6 digits significant. (a = 7; b=1 ; c=1) Ycg =
Given the reference system, determine the coordinate of the centroid Ycg of the symmetrical plane figure. For therefore, adopt the value of L = 100 + 10·a + 20·(b + 2·c) {mm}. Consider a minimum precision of 6 digits significant. (a = 7; b=1 ; c=1) Ycg =
International Edition---engineering Mechanics: Statics, 4th Edition
4th Edition
ISBN:9781305501607
Author:Andrew Pytel And Jaan Kiusalaas
Publisher:Andrew Pytel And Jaan Kiusalaas
Chapter9: Moments And Products Of Inertia Of Areas
Section: Chapter Questions
Problem 9.46P
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Question
Given the reference system, determine the coordinate of the centroid Ycg of the symmetrical plane figure. For therefore, adopt the value of L = 100 + 10·a + 20·(b + 2·c) {mm}. Consider a minimum precision of 6 digits significant. (a = 7; b=1 ; c=1)
Ycg =
![0,5-L 0,5-L
6-L
1,5-L
L
3-L -- 3-L](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F0fdea3dd-f249-4dc2-af82-9d8ab2ce8272%2Fd638e08f-0815-4eb9-8312-5130a15b8602%2Fh5pkul9_processed.png&w=3840&q=75)
Transcribed Image Text:0,5-L 0,5-L
6-L
1,5-L
L
3-L -- 3-L
![Question resolution form:
- CG Y coordinate (Yeg) for composite sections Yeg
- Moments of Inertia of Composite Sections
Ix-Σ (+)?-4)
- Moments of inertia (Ix and ly) about the centroid for rectangles and triangles:
Ix = (b-h³)/12
lby=(h-b³)/12
Ix = (b -h)/36
|hy= (h•b³)/36
h/2
CG
h/2
b/2' b/2
b/3 b
h/3](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F0fdea3dd-f249-4dc2-af82-9d8ab2ce8272%2Fd638e08f-0815-4eb9-8312-5130a15b8602%2F4juc3aq_processed.png&w=3840&q=75)
Transcribed Image Text:Question resolution form:
- CG Y coordinate (Yeg) for composite sections Yeg
- Moments of Inertia of Composite Sections
Ix-Σ (+)?-4)
- Moments of inertia (Ix and ly) about the centroid for rectangles and triangles:
Ix = (b-h³)/12
lby=(h-b³)/12
Ix = (b -h)/36
|hy= (h•b³)/36
h/2
CG
h/2
b/2' b/2
b/3 b
h/3
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